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Chapter 5: Q4. (page 180)

Draw in a plane of symmetry for each molecule.

a.

b.

c.

d.

Short Answer

Expert verified

a.

b.

c.

d.

Step by step solution

01

Plane of symmetry

An imaginary plane that bisects a molecule dividing it into two equal/identical halves is termed plane of symmetry.

02

Plane of symmetry and chirality

Molecules that possess a mirror plane or plane of symmetry are termed achiral and the ones that do not possess a plane of symmetry are termed chiral.

03

Plane of symmetry of the given molecules

The plane of symmetry of the given molecules are as follows:

a.

Plane of symmetry in compound a

b.

Plane of symmetry in compound b

c.

Plane of symmetry in compound c

d.

Plane of symmetry in compound d

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Most popular questions from this chapter

Give the IUPAC name for each compound, including the R,S designation for each stereogenic center.

a.

b.

c.

The facts in Section 5.4A can be used to locate stereogenic centers in any molecule, no matter how complicated. Always look for carbons surrounded by four different groups. With this in mind, locate the four stereogenic centers in aliskiren, a drug introduced in 2007 for the treatment of hypertension.

Artemisinin and mefloquine are widely used antimalarial drugs. A ball-and-stick model of artemisinin appears on the cover of this text.

  1. Locate the stereogenic centers in both drugs.
  2. Label each stereogenic center in mefloquine as R or S.
  3. What is the maximum number of stereoisomers possible for artemisinin?
  4. How are the N atoms in mefloquine hybridized?
  5. Can two molecules of artemisinin intermolecularly hydrogen bond to each other?
  6. What product is formed when mefloquine is treated with HCl?

Which of the following cyclic molecules are meso compounds?

a.

b.

c.

Which group in each pair is assigned the higher priority?

a. -CH3,-CH2CH3

b. -I,-Br

c. -H,-D

d. -CH2Br,-CH2CH2Br

e. localid="1648296449951" -CH2Cl,-CH2CH(CH3)2

f.-CH2OH,-CHO
See all solutions

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