Question: Anacin is an over-the-counter pain reliever that contains aspirin and caffeine. Answer the following questions about each compound:

a. What is the molecular formula?

b. How many lone pairs are present on heteroatoms?

c. Label the hybridization state of each carbon.

d. Draw three additional resonance structures.

Short Answer

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Answer

a. The molecular formulas of aspirin and caffeine are C9H8O4andC8H10N4O2, respectively.

b. The numbers of lone pairs on heteroatoms of aspirin and caffeine are 8 and 8, respectively.


c. and ,respectively.

d. and

,respectively.

Step by step solution

01

Step-by-Step Solution Step 1: Molecular formula

The individual atom’s count, which is taking part in the skeletal structure, is shown in the compact structure. So, the compact structure of the corresponding skeletal structure is known as the molecular formula.

02

Determination of the number of lone pairs

The number of lone pairs is determined based on the valence electrons and bonding pairs.

Suppose an atom has six valence electrons and two bond pairs, so now the atom is left with 4 electrons or two lone pairs.

03

Hybridization

The multiplicity of bonds usually determines the hybridization as mentioned below:

  • The single-bonded carbon has sp3 hybridization.
  • The double-bonded carbon has sp2 hybridization.
  • The triple-bonded carbon has sp hybridization.
04

Information of given compounds

a. The skeletal structure of aspirin is formed by nine carbons, four oxygens, and eight hydrogens. Therefore, its molecular formula is C9H8O4.

The skeletal structure of caffeine is formed by 8 C, 2 O, 4 N, and 10 H. Therefore, its molecular formula is C8H10N4O2.

b. In the skeletal structure of aspirin and caffeine, oxygen and nitrogen are heteroatoms.

In the case of aspirin, oxygen has six valence electrons, and only two of them are involved in forming the bond.

Thus, the two lone pairs are available on each oxygen atom. Hence, a total of eight lone pairs are present in the structure.

In the case of caffeine, nitrogen has five valence electrons, and only three of them are involved in forming the bond.

Thus, the one lone pair is available on each nitrogen atom. Hence, eight lone pairs (four on nitrogen and four lone pairs on oxygen) are present in the structure.

c. In the skeletal structures of aspirin and caffeine, it is clear that only double bonds and single bonds are present. So,sp3 hybridization is placed on single-bonded carbon and sp2for double-bonded carbon.

Aspirin Caffeine

d.Resonance shows the hypothetical images obtained when pi electrons or non-bonding electrons move from one orbital to another.

Here, the resonance structures of aspirin and caffeine are represented as follows:

Resonance structures of aspirin

Resonance structures of caffeine

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Question: Draw an acceptable Lewis structure from each condensed structure, such that all atoms have zero formal charges.

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Question: The curved arrow notation introduced in Section 1.6 is a powerful method used by organic chemists to show the movement of electrons not only in resonance structures but also in chemical reactions. Since each curved arrow shows the movement of two electrons, following the curved arrows illustrates what bonds are broken and formed in a reaction. Consider the following three-step process: (a) Add curved arrows in Step [1] to show the movement of electrons. (b) Use the curved arrows drawn in Step [2] to identify the structure of X; X is converted in Step [3] to phenol and HCl.

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