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Chapter 6: Problem 6.29 (page 241)

Use full-headed or half-headed curved arrows to show the movement of electrons in each reaction.

a.

b.

c.

d.

Short Answer

Expert verified

Answer

a.

b.

c.

d.

Step by step solution

01

Step-by-Step SolutionStep 1: Full-headed and Half-headed curved arrows

A full-headed arrow is used to indicate the movement/transfer of a pair of electrons.

A half-headed arrow indicates the transfer of a single electron.

02

Movement of electrons in reaction a and b

The movement of electrons in reactions a and b are as follows:

a.

Reaction a

b.Reaction b

03

Movement of electrons in reaction c and d

The movement of electrons in reactions c and dare as follows:

c.

Reaction c

d.Reaction d

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Most popular questions from this chapter

Draw an energy diagram for a two-step reaction, A→B→C, where the relative energy of these compounds is C<A<B, and the conversion of B→Cis rate-determining.

(a) Draw in the curved arrows to show how A is converted to B in Step [1]. (b) Identify X, using the curved arrows drawn for Step [2].

The conversion of acetyl chloride to methyl acetate occurs via the following two-step mechanism:

a. Add curved arrows to show the movement of the electrons in each step.

b. Write the rate equation for this reaction, assuming the first step is rate-determining.

c. If the concentration of were increased 10 times, what would happen to the rate of the reaction?

d. If the concentrations of both and were increased 10 times, what would happen to the rate of the reaction?

e. Classify the conversion of acetyl chloride to methyl acetate as an addition, elimination, or substitution.

For each rate equation, what effect does the indicated concentration change have on the overall rate of the reaction?

[1] rate=k[CH3CH2Br][-OH]

  1. tripling the concentration of CH3CH2Bronly
  2. tripling the concentration of – OH only
  3. tripling the concentration of both CH3CH2Br and – OH

[2]role="math" localid="1648280223497" rate=k[(CH3)3COH]

  1. doubling the concentration of (CH3)3COH
  2. increasing the concentration of (CH3)3COH by a factor of 10

Draw the products of homolysis or heterolysis of each indicated bond. Use electronegativity differences to decide on the location of charges in the heterolysis reaction. Classify each carbon reactive intermediate as a radical, carbocation, or carbanion.

a.

b.
See all solutions

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