Explain why HCCHis more acidic than CH3CH3, even though the C-H bond in HCCHhas a higher bond dissociation energy than the C-H bond in CH3CH3.

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Answer

This implies that the alkynes are more acidic than the alkanes due to the greater stability of the conjugate base of alkyne.

Step by step solution

01

Step-by-Step SolutionStep 1: Bond dissociation energy

The strength of a chemical bond can be determined by the bond dissociation energy. It is the energy required to break a chemical bond homolytically and results in the formation of free radicals in the gaseous phase.

02

Acidity of hydrocarbons

Among the hydrocarbons, alkanes are considered to be neutral molecules. Alkanes are the least acidic among the alkenes and alkynes. This is because of the almost similar electronegativity of carbon and hydrogen atoms; the loss of protons becomes very difficult.

On the other hand, the akenes and alkynes are acidic due to the increased s character in their hybridized orbitals. As a result, the loss of protons becomes easier.

03

Alkynes are more acidic than alkanes

The alkynes are more acidic than alkanes. The acidic nature of alkynes can be explained as follows:

  • The bond dissociation energy of the alkynes is more than the alkanes due to the greater percentage of s character. In alkynes, the carbon atom is sp hybridized, and the hybrid orbitals have about 50 percent s character.
  • In the case of alkane molecules, the carbon atom is sp3, and the hybrid orbitals have 25 percent s character. As a result of the high s character, the carbon-hydrogen bond becomes stronger and shorter, and the bond dissociation energy increases.
  • The alkynes are more acidic than alkanes due to the high stability of their conjugate base. The conjugate base of an alkane ( CH3CH2-) results from the sp3hybrid carbon atom.
  • On the other hand, the conjugate base of an alkyne (CHC-) results from the sp hybrid orbital of carbon atoms which have 50 percent s character. The higher character results in the stabilization of the conjugate base of the alkyne molecule.

This implies that the alkynes are more acidic than the alkanes due to the greater stability of the conjugate base of alkyne.

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Most popular questions from this chapter

The conversion of (CH3)3Clto (CH3)2C=CH2can occur by either a one-step or a two-step mechanism, as shown in Equations [1] and [2].

a. What rate equation would be observed for the mechanism in Equation [1]?

b. What rate equation would be observed for the mechanism in Equation [2]?

c. What is the order of each rate equation (i.e., first, second, and so forth)?

d. How can these rate equations be used to show which mechanism is the right one for this reaction?

e. Assume Equation [1] represents an endothermic reaction and draw an energy diagram for the reaction. Label the axes, reactants, products, Ea, and H°. Draw the structure for the transition state.

f. Assume Equation [2] represents an endothermic reaction and that the product of the rate-determining step is higher in energy than the reactants or products. Draw an energy diagram for this two-step reaction. Label the axes, reactants and products for each step, and the Eaand H°for each step. Label H°overall. Draw the structure for both transition states.

Use the values in Table 6.2 to calculatefor each reaction. Classify each reaction as endothermic or exothermic.

a.

b.

Follow the curved arrows and draw the products of the following reaction.

The equilibrium constant for the conversion of the axial to the equatorial conformation of methoxycyclohexane is 2.7.


  1. Given these data, which conformation is present in the larger amount at equilibrium?
  2. Is ΔG° for this process positive or negative?
  3. From the values in Table 6.3, approximate the size of ΔG°.

Answer Problem 6.14 for a reaction with ΔH°=-20kJ/mol.

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