Which bond in each pair has the higher bond dissociation energy?

a.

b.

Short Answer

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a.

b.

Step by step solution

01

Step-by-Step SolutionStep 1: Bond dissociation energy

The amount of energy that is essential to break a chemical bond is termed the bond dissociation energy.

02

Factors affecting bond dissociation energy

Size of the bonded atoms: As the size of the bonded atom increases the bond length increases and the bond strength decreases thereby decreasing the bond dissociation energy.

The number of electrons involved in bonding: As the number of electrons shared between two atoms (i.e., the number of bonds between two atoms) increases the bond strength increases and thus the bond dissociation energy also increases.

03

Bonds with high bond dissociation energy

a.

The compound with higher bond dissociation energy

The first compound consists of a carbon-oxygen (C-O) and the second compound consists of a carbon-sulfur (C-S) bond.

Since sulfur is bigger in size than oxygen the carbon-sulfur (C-S) bond is weaker compared to the carbon-oxygen (C-O) bond.

Therefore, the carbon-oxygen (C-O) bond has higher bond dissociation energy than the carbon-sulfur (C-S) bond.

b.

Compound with higher bond dissociation energy

The first compound consists of a carbon-oxygen double bond while the second one has a carbon-oxygen single bond.

Since a double bond has higher bond strength than a single bond, the carbon-oxygen double bond (C=O) has higher bond dissociation energy than the carbon-oxygen single bond (C-O).

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Most popular questions from this chapter

a. Which Keqcorresponds to a negative value of localid="1648198317845" ΔG, localid="1648198334107" Keq=1000 or Keq= 0.001 ?

b. Which Keqcorresponds to a lower value oflocalid="1648198364090" ΔG, localid="1648198396853" Keq=10-2or localid="1648198411007" Keq=10-5?

Indicate which factors affect the rate of a reaction.

  1. G°
  2. H°
  3. Ea
  4. Temperature
  5. concentration
  6. width="28">Keq
  7. k
  8. Catalysts

Calculate ΔH° for each reaction.

  1. HO·+CH4.CH3+H2O
  2. CH3OH+HBrCH3Br+H2O

The Diels–Alder reaction, a powerful reaction discussed in Chapter 16, occurs when a 1,3- diene such as A reacts with an alkene such as B to form the six-membered ring in C.

a. Draw curved arrows to show how A and B react to form C.

b. What bonds are broken and formed in this reaction?

c. Would you expect this reaction to be endothermic or exothermic?

d. Does entropy favor the reactants or products?

e. Is the Diels–Alder reaction a substitution, elimination, or addition?

The conversion of (CH3)3Clto (CH3)2C=CH2can occur by either a one-step or a two-step mechanism, as shown in Equations [1] and [2].

a. What rate equation would be observed for the mechanism in Equation [1]?

b. What rate equation would be observed for the mechanism in Equation [2]?

c. What is the order of each rate equation (i.e., first, second, and so forth)?

d. How can these rate equations be used to show which mechanism is the right one for this reaction?

e. Assume Equation [1] represents an endothermic reaction and draw an energy diagram for the reaction. Label the axes, reactants, products, Ea, and H°. Draw the structure for the transition state.

f. Assume Equation [2] represents an endothermic reaction and that the product of the rate-determining step is higher in energy than the reactants or products. Draw an energy diagram for this two-step reaction. Label the axes, reactants and products for each step, and the Eaand H°for each step. Label H°overall. Draw the structure for both transition states.

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