Draw structural formulas for the three secondary amines with the molecular formula \(\mathrm{C}_{4} \mathrm{H}_{11} \mathrm{~N}\).

Short Answer

Expert verified
Answer: There are 3 possible structural formulas of secondary amines for the given molecular formula: 1. N - (\(C_{1}\))3H - \(C_{2}\) - \(C_{3}\) - \(C_{4}\) 2. N - \(C_{1}\)-(\(C_{1'}\))3H - \(C_{2}\)-(\(C_{2'}\))3H 3. N - \(C_{1}\) - \(C_{2}\) - \(C_{3}\) - (\(C_{4}\))3H

Step by step solution

01

Identify the Nitrogen Atom

The nitrogen atom is connected to two carbon atoms in a secondary amine. Let's denote these two carbon atoms as \(C_{1}\) and \(C_{2}\).
02

Distribute the Remaining Carbon Atoms

As there are 4 carbon atoms in the molecular formula, we have 2 carbon atoms remaining. We can distribute these carbon atoms between \(C_{1}\) and \(C_{2}\) in three possible ways: 1. \(C_{1}\) has 0 remaining carbon atoms and \(C_{2}\) has 2 remaining carbon atoms. 2. \(C_{1}\) has 1 remaining carbon atom and \(C_{2}\) has 1 remaining carbon atom. 3. \(C_{1}\) has 2 remaining carbon atoms and \(C_{2}\) has 0 remaining carbon atoms.
03

Configure Hydrogen Atoms in Each Case

Now we need to configure the remaining hydrogen atoms for each case in order to satisfy the valency requirement for each carbon atom. 1. In the first case, \(C_{1}\) has 0 remaining carbon atoms and \(C_{2}\) has 2 remaining carbon atoms. As there are 11 hydrogen atoms in the molecular formula, \(C_{1}\) has 3 hydrogen atoms and \(C_{2}\) has 8 hydrogen atoms. The structural formula is: H | N - \(C_{1}\) - \(C_{2}\) - \(C_{3}\) - \(C_{4}\) | H 2. In the second case, \(C_{1}\) has 1 remaining carbon atom and \(C_{2}\) has 1 remaining carbon atom. As there are 11 hydrogen atoms in the molecular formula, the hydrogen atoms are distributed between \(C_{1}\) and \(C_{2}\) as follows: - \(C_{1}\) has 2 hydrogen atoms - \(C_{1'}\) (attached to \(C_{1}\)) has 3 hydrogen atoms - \(C_{2}\) has 2 hydrogen atoms - \(C_{2'}\) (attached to \(C_{2}\)) has 3 hydrogen atoms The structural formula is: H | N - \(C_{1}\) - \(C_{1'}\) - \(C_{2}\) - \(C_{2'}\) | H 3. In the third case, \(C_{1}\) has 2 remaining carbon atoms and \(C_{2}\) has 0 remaining carbon atoms. As there are 11 hydrogen atoms in the molecular formula, \(C_{1}\) has 8 hydrogen atoms and \(C_{2}\) has 3 hydrogen atoms. The structural formula is: H | N - \(C_{1}\) - \(C_{2}\) - \(C_{3}\) - \(C_{4}\) | H So our three structural formulas for the given molecular formula are: 1. N - (\(C_{1}\))3H - \(C_{2}\) - \(C_{3}\) - \(C_{4}\) 2. N - \(C_{1}\)-(\(C_{1'}\))3H - \(C_{2}\)-(\(C_{2'}\))3H 3. N - \(C_{1}\) - \(C_{2}\) - \(C_{3}\) - (\(C_{4}\))3H

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