Chapter 10: Problem 133
Thiols are much more acidic than alcohols.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Chapter 10: Problem 133
Thiols are much more acidic than alcohols.
These are the key concepts you need to understand to accurately answer the question.
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Get started for freeAccording to the principle of microscopic reversibility, the sequence of transition states and reartive intermediates (that is, the mechanism) for any reversible reaction must be the sime, but in reverse order, for the reverse reaction as for the forward reaction.
Proton transfer to the OH group to form an oxconium ion (add a proton)
followed ly loss of \(\mathrm{H}_{2} \mathrm{O}\) (break a bond to give stable
molecules or ions) gives a \(2^{\text {" carbocation }}\) intermediate.
Miggration of a methyl group with its bonding pair of electrons from the
adjacent carbon to the positively charged carbon gives a more stable \(3^{\text
{" }}\) carbocation (1,2shift). Proton transfer from this intermediate to a
base, here shown as \(\mathrm{H}_{2} \mathrm{O}\), gives the ohserved product
(take a proton away).
Using your roadnap as a guide, show hoes to comvert 4-methyl-1-pentene into S-lbethyhexanenitrile. You must use 4-1bethyl-1-pentene and sodium cyanide as the source of all carbon atoms in the target molecule. Show all reagents needed and all molecules symthesized along the way.
Two diastereomeric sets of enantiomers, \(A / \mathrm{B}\) and \(\mathrm{C} /
\mathrm{D}\), exist for S-bromo-2-butanol.
Malve a new bond between a nucleophile and an electrophile and simultaneously
break a bond to give stable molecules or ions. Nucleophilic displacement of
MEO by Br gives the bromoalkane.
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