Following is the \({ }^{1} \mathrm{H}\)-NMR spectrum of compound \(\mathrm{O}\), molecular formula \(\mathrm{C}_{7} \mathrm{H}_{12}\) Compound \(\mathrm{O}\) reacts with bromine in carbon tetrachloride to give a compound with the molecular formula \(\mathrm{C}_{7} \mathrm{H}_{12} \mathrm{Br}_{2}\). The \({ }^{13} \mathrm{C}-\mathrm{NMR}\) spectrum of compound \(\mathrm{O}\) shows signals at \(\delta 150.12,106.43,35.44,28.36\), and \(26.36\). Deduce the structural formula of compound \(\mathrm{O}\).

Short Answer

Expert verified
Answer: The structural formula of compound O is an internal alkene having six carbons in a straight chain with a methyl group at the center.

Step by step solution

01

Identify the number of atoms in the molecular formula

The molecular formula of compound O is C7H12, which means it has seven carbon atoms and twelve hydrogen atoms.
02

Analyze the given NMR spectra data

We are given five signals in the 13C-NMR spectrum, which indicates that there are five different carbon environments in the compound. Also, we have two signals in the 1H-NMR spectrum, indicating the presence of two different proton environments.
03

Deduce possible structural formula based on NMR data

Considering the NMR data, we can deduce the following about the compound's structure: - Two carbon atoms with a chemical shift of around 150 and 106 are likely part of a double bond or a carbonyl group. - The other three carbon atoms with chemical shifts of around 35, 28, and 26 are likely part of an aliphatic environment. - There are two different proton environments giving two signals in the 1H-NMR spectrum, which could mean there are two different sets of protons in the compound. Based on this information, we can deduce the following possible structural formula: an internal alkene having six carbons in a straight chain with a methyl group at the center.
04

Verify the compound reacts with bromine to form the given product

The given reaction is: Compound O + Br2 -> C7H12Br2 The proposed internal alkene, with six carbons in a straight chain and a methyl group at the center, can react with bromine in a typical halogenation reaction where the double bond breaks and two bromine atoms add across the double bond. This results in the formation of the product with the molecular formula C7H12Br2 as given. Thus, the structural formula of compound O is an internal alkene having six carbons in a straight chain with a methyl group at the center.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

13C-NMR Spectrum Analysis
13C-NMR spectroscopy is a valuable tool in organic chemistry for determining the structures of carbon-containing compounds. By analyzing the carbon-13 NMR spectrum, chemists can deduce the different carbon environments present in a molecule. Each unique carbon environment results in a separate signal at a specific chemical shift, measured in parts per million (ppm).

The chemical shift gives insights into the electronic environment of the carbons. For instance, downfield shifts (higher ppm values) typically indicate carbons bonded to electronegative atoms like oxygen or nitrogen, or those in pi bonds, such as in alkenes or aromatic systems. On the other hand, upfield shifts (lower ppm values) often associate with carbons in saturated environments such as alkanes.

Interpretation involves matching the observed chemical shifts with known reference values for various carbon types. Significant to remember is that the number of signals correlates with the number of distinct carbon environments, helping to piece together the compound's structure.
1H-NMR Spectrum Interpretation
1H-NMR spectroscopy complements its 13C counterpart by focusing on hydrogen atoms. It provides insights into how many different proton environments exist within a molecule. Just like the 13C-NMR, the 1H-NMR spectrum displays chemical shifts in ppm, which vary depending on the neighboring atoms and the type of chemical bonds.

Chemical shifts toward higher frequencies (downfield), near 6-8 ppm, often signify protons on carbons adjacent to double bonds or aromatic rings. In contrast, protons on saturated carbons resonate at lower frequencies (upfield) typically between 0.5-5 ppm. The area under each signal, known as the integral, reflects the number of protons contributing to that signal.

Coupling patterns, observed as splitting of signals, can further unravel the proximity and number of neighboring hydrogen atoms, giving an even clearer picture of the molecular structure. When interpreting a 1H-NMR spectrum, all these features must be considered to accurately deduce the molecular structure.
Molecular Structure Deduction
Deducing the molecular structure from NMR spectroscopy involves synthesizing the information from both the 13C and 1H spectra. After identifying the number and type of carbon and hydrogen environments, chemists can begin to piece together the puzzle of the molecule's architecture. Structural isomers pose a particular challenge as they may have the same molecular formula but different structural arrangements.

The approach often begins by identifying the core skeleton—determining which carbons form the backbone of the molecule and how they're connected. The presence of functional groups is then inferred from specific chemical shift regions. Lastly, the integration and multiplicity of the 1H signals can help locate the relative positioning of protons to one another.

Combining these data points allows chemists to construct a reasonable structure that accounts for the molecular formula and the observed NMR characteristics, eventually deducing the most probable chemical structure for the compound in question.
Alkene Bromination Reaction
Alkene bromination is a specific type of halogenation reaction where bromine (Br2) adds across the double bond of an alkene, resulting in a vicinal dibromide. This reaction occurs typically in a non-polar solvent such as carbon tetrachloride (CCl4).

During the reaction, the pi electrons of the alkene attack the bromine molecule causing heterolytic fission of the Br-Br bond. A cyclic bromonium ion intermediate forms, and then nucleophilic attack by another bromide ion results in the vicinal dibromide product. It is stereospecific, meaning that the two bromine atoms will add to opposite faces of the double bond, producing a trans product when the alkene is cyclic.

Understanding this reaction is crucial when deducing structures, as observing a new molecular formula featuring additional bromine atoms indicates that a bromination reaction has occurred, revealing the existence and position of the alkene within the original molecule.

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Most popular questions from this chapter

The line of integration of the two signals in the \({ }^{1} \mathrm{H}-\mathrm{NMR}\) spectrum of a ketone with the molecular formula \(\mathrm{C}_{7} \mathrm{H}_{14} \mathrm{O}\) rises 62 and 10 chart divisions, respectively. Calculate the number of hydrogens giving rise to each signal, and propose a structural formula for this ketone.

Four important types of structural information can be obtained from a \({ }^{1} \mathrm{H}-\mathrm{NMR}\) spectrum. \- From the number of signals, we can determine the number of sets of equivalent hydrogens. \- From the integration of signal areas, we can determine the relative numbers of hydrogens in each set. \- From the chemical shift of each signal, we can derive information about the chemical environment of the hydrogens in each set. \- From the splitting pattern of each signal, we can derive information about the number and chemical equivalency of hydrogens on the same and adjacent carbon atoms, in other words the connectivities between different groups on the molecule.

The C-NMR spectrum of 3-methyl-2-butanol shows signals at \(\delta 17.88\left(\mathrm{CH}_{3}\right), 18.16\) \(\left(\mathrm{CH}_{3}\right), 20.01\left(\mathrm{CH}_{3}\right), 35.04\) (carbon-3), and \(72.75\) (carbon-2). Account for the fact that each methyl group in this molecule gives a different signal.

According to the \((n+1)\) rule, if a hydrogen has \(n\) hydrogens nonequivalent to it but equivalent among themselves on the same or adjacent atom(s), its \({ }^{1} \mathrm{H}-\mathrm{NMR}\) signal will be split into \((n+1)\) peaks. \- Splitting patterns are commonly referred to as singlets (s), doublets (d), triplets \((t)\), quartets \((q)\), quintets, and multiplets ( \(m\) ). \- The relative intensities of peaks in a multiplet can be predicted from an analysis of spin combinations for adjacent hydrogens or from the mnemonic device called Pascal's triangle. \- A coupling constant \((J)\) is the distance between adjacent peaks in a multiplet and is reported in hertz \((\mathrm{Hz})\). The value of \(J\) depends only on internal fields within a molecule and is independent of the spectrometer field.

\- The key relationship for NMR is that the difference in energy between the \(+\frac{1}{2}\) and \(-\frac{1}{2}\) nuclear spin states is proportional to the strength of the magnetic field experienced by a given nucleus.

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