The \({ }^{13} \mathrm{C}\) NMR spectrum of s-methyl-2-butanol shows signals at \(\delta 17.88\left(\mathrm{CH}_{3}\right), 18.16\) \(\left(\mathrm{CH}_{3}\right), 20.01\left(\mathrm{CH}_{3}\right), 35.04\) (carbon-3), and \(72.75\) (carbon-2). Account for the fact that each methyl group in this molecule gives a different signal.

Short Answer

Expert verified
Based on the provided step-by-step solution, the short answer is: Each methyl group in s-methyl-2-butanol gives a different signal in the ${ }^{13}C$ NMR spectrum because they are in different chemical environments due to the influence of the hydroxyl group. The different levels of shielding and deshielding caused by the presence of the hydroxyl group result in distinct NMR signals for each methyl group.

Step by step solution

01

Draw the structure of s-methyl-2-butanol

First, draw the structural formula of s-methyl-2-butanol: \(CH_3CH_2C(CH_3)(OH)CH_3\)
02

Identify the three different methyl groups

There are three methyl (\(\mathrm{CH}_{3}\)) groups in s-methyl-2-butanol. These are: 1. The methyl group attached to the carbon with the hydroxyl group (OH) - \(\left(1\right)\) 2. The terminal methyl group (CH3CH2-) - \(\left(2\right)\) 3. The methyl group attached to the middle carbon - \(\left(3\right)\)
03

Understand NMR signals and chemical environment

NMR signals depend on the electronic environment experienced by the nucleus (in this case, carbon-13). Different chemical environments of the same atom type in a molecule will give different signals. Since we have three different methyl groups in our molecule, they could potentially be in different chemical environments, leading to different NMR signals.
04

Analyze the chemical environments of the methyl groups

Now, analyze the chemical environment of each methyl group: 1. Methyl group \(\left(1\right)\) is attached to a carbon bearing a hydroxyl (\(\mathrm{OH}\)) group, which is an electron-withdrawing group. This will deshield the carbon and change the chemical environment slightly. 2. Methyl group \(\left(2\right)\) is a regular terminal methyl group, which is not directly attached to any electron-withdrawing groups. 3. Methyl group \(\left(3\right)\) is attached to a carbon that is connected to a hydroxyl group, making it indirectly influenced by the electron-withdrawing effect of the hydroxyl group on the carbon chain.
05

Relate chemical environment to NMR signals

Since the three methyl groups are in different chemical environments due to the influence of the hydroxyl group, they will have different levels of shielding and deshielding. As a result, each methyl group will give a different signal in the \({ }^{13}\mathrm{C}\) NMR spectrum, as observed in the problem statement: \(\delta 17.88\left(\mathrm{CH}_{3}\right), 18.16\left(\mathrm{CH}_{3}\right), 20.01\left(\mathrm{CH}_{3}\right)\) In conclusion, each methyl group in s-methyl-2-butanol gives a different signal in the \({ }^{13} \mathrm{C}\) NMR spectrum due to their distinct chemical environments influenced by the presence of the hydroxyl group in the molecule.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chemical Environment in NMR Spectroscopy
Carbon-13 NMR spectroscopy is an invaluable tool for chemists to deduce the structure of organic molecules. It works on the principle that carbon atoms in different chemical environments will resonate at different frequencies when placed in a magnetic field. A chemical environment in NMR spectroscopy is determined by the surrounding atoms and groups connected to the carbon atom in question.

The electrons around a carbon atom generate a local magnetic field that can either augment or oppose the external magnetic field applied in the NMR spectrometer. This interaction affects the chemical shift, represented as delta \(\delta\), and measured in parts per million (ppm). The more shielded a nucleus is by its electron cloud, the lower the chemical shift value it will exhibit, while deshielded nuclei resonate at higher chemical shift values.

Understanding these shifts and discerning the unique pattern for each different chemical environment allows us to dissect the molecular structure. For example, a carbon atom bonded to an electronegative atom like oxygen might experience deshielding, and thus, its chemical shift will be at a higher value compared to a carbon bonded to less electronegative atoms. In complex molecules, each carbon will typically have a unique resonance peak, reflecting its unique electronic surrounding.
Methyl Groups in NMR
In carbon-13 NMR spectroscopy, methyl groups (\(\mathrm{CH}_{3}\)) often appear as distinct signals. While one might expect identical groups such as methyls to have similar NMR signals, this is not always the case. The signal variation arises because the position of the methyl group within the molecule can influence its chemical environment significantly. For instance, a methyl group attached directly to an electronegative atom will present a different signal than one located at the end of an alkyl chain.

Each methyl group in a given molecule can resonate at a slightly different frequency due to slight variations in electronic shielding, even if the differences are subtle. Methyl groups can thus act as sensitive probes in a molecular structure, allowing chemists to infer the proximity to varying functional groups or differing levels of saturation in the molecule. When interpreting carbon-13 NMR spectra, it's essential to consider these nuances to accurately analyze the molecular structure and understand the chemical environment in which each methyl group resides.
Shielding and Deshielding in NMR
The concepts of shielding and deshielding are central to understanding how NMR spectroscopy works. Shielding occurs when electron density around a nucleus repels the external magnetic field, effectively 'shielding' the nucleus. This results in a chemical shift that is upfield (at a lower delta value). Conversely, deshielding occurs when the electron density is low or when electronegative atoms pull the electron density away from the nucleus, allowing the external magnetic field to have a more substantial impact. This gives rise to a downfield chemical shift (at a higher delta value).

In the context of a molecule such as s-methyl-2-butanol, various factors can lead to differences in shielding and deshielding. The presence of electron-donating or electron-withdrawing groups, hybridization of carbon atoms, and magnetic anisotropy induced by pi bonds all contribute to the shifts observed in the NMR spectrum. These effects enable chemists to distinguish between seemingly identical groups, like the methyl groups in s-methyl-2-butanol, based on the distinct physical conditions they experience within the molecule. Recognizing these subtle changes is key to interpreting NMR data and elucidating complex molecular structures.

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Most popular questions from this chapter

Four important types of structural information can be obtained from a \({ }^{1} \mathrm{H}-\mathrm{NMR}\) spectrum. \- From the number of signals, we can determine the number of sets of equivalent hydrogens. \- From the integration of signal areas, we can determine the relative numbers of hydrogens in each set. \- From the chemical shift of each signal, we can derive information about the chemical environment of the hydrogens in each set. \- From the splitting pattern of each signal, we can derive information about the number and chemical equivalency of hydrogens on the same and adjacent carbon atoms, in other words the connectivities between different groups on the molecule.

Molecules in which substitution produces diastereomers are called diastereotopic. - Diastereotopic atoms are nonequivalent in all environments so they have different chemical shifts. These differences can lead to complex splitting of the signals of diastereotopic \(\mathrm{H}\) atoms, especially those adjacent to a chiral center.

Propose a structural formula for compound \(\mathrm{J}\), molecular formula \(\mathrm{C}_{3} \mathrm{H}_{6} \mathrm{O}\), consistent with the following \({ }^{1}\) H-NMR spectrum.

Explain how to distinguish between the members of each pair of constitutional isomers based on the number of signals in the proton-decoupled \({ }^{13} \mathrm{C}-\mathrm{NMR}\) spectrum of each member.

Compound \(\mathrm{K}\), molecular formula \(\mathrm{C}_{8} \mathrm{H}_{14} \mathrm{O}\), readily undergoes acid-catalyzed dehydration when warmed with phosphoric acid to give compound L, molecular formula \(\mathrm{C}_{6} \mathrm{H}_{12}\), as the major organic product. The \({ }^{1} \mathrm{H}\)-NMR spectrum of compound \(\mathrm{K}\) shows signals at \(\delta 0.90(\mathrm{t}, 6 \mathrm{H}), 1.12(\mathrm{~s}, 3 \mathrm{H}), 1.38(\mathrm{~s}, 1 \mathrm{H})\), and \(1.48(\mathrm{q}, 4 \mathrm{H})\). The \({ }^{19} \mathrm{C}-\mathrm{NMR}\) spectrum of compound \(\mathrm{K}\) shows signals at \(\delta 72.98,33.72,25.85\), and 8.16. Deduce the structural formulas of compounds \(\mathrm{K}\) and \(\mathrm{L}\).

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