Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 18: Problem 6

Complete the following transesterification reaction (the stoichiometry is given in the equation).

Short Answer

Expert verified
Answer: In a transesterification reaction, the reactants are an ester (RCOOR") and an alcohol (R'OH), and the products are a new ester (RCOOR') and a byproduct (R"OH). The stoichiometry of the reaction is 1:1:1:1.

Step by step solution

01

Identify the reactants and products

In a transesterification reaction, the reactants are an ester and an alcohol, and the products are a new ester and a byproduct. We need to identify the reactants and products in the given equation. Ester: RCOOR" Alcohol: R'OH New Ester: RCOOR' Byproduct: R"OH
02

Determine the stoichiometry of the reaction

The stoichiometry of the reaction is given in the equation. In a transesterification reaction, one mole of ester reacts with one mole of alcohol to produce one mole of new ester and one mole of byproduct. The stoichiometry of the reaction is 1:1:1:1.
03

Write the balanced reaction equation

Now we can write the balanced reaction equation for the transesterification reaction using the identified reactants, products, and stoichiometry. RCOOR" + R'OH -> RCOOR' + R"OH
04

Complete the transesterification reaction

With the balanced reaction equation, the transesterification reaction is complete. The reactants, an ester (RCOOR") and an alcohol (R'OH), react to form a new ester (RCOOR') and a byproduct (R"OH), with the stoichiometry of 1:1:1:1.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Treating choline with acetic anhydride gives acetylcholine, a neurotransmitter. Write an equation for the formation of acetylcholine.

Draw a structural formula for each compound. (a) NCyclohexylacetamide (b) 1-Methylpropyl methanoate (c) Cyclobutyl butanoate (d) \(N\) (1-Methylheptyl) succinimide (e) Diethyl adipate (f) 2-Aminopropanamide

Propose a synthesis for diphenhydramine starting from benzene, benzoic acid, and 2- \((N, N-\) dimethylamino) ethanol.

Barbiturates are prepared by treating a derivative of diethyl malonate with urea in the presence of sodium ethoxide as a catalyst. Following is an equation for the preparation of barbital, a long-duration hypnotic and sedative, from diethyl diethylmalonate and urea. Barbital is prescribed under one of a dozen or more trade names. (a) Propose a mechanism for this reaction. (b) The \(\mathrm{p} K_{\mathrm{a}}\) of barbital is \(7.4\). Which is the most acidic hydrogen in this molecule? How do you account for its acidity?

Following is a retrosynthetic analysis for the synthesis of the herbicide ( \(S\) )-Metolachlor from 2-ethyl-6-methylaniline, chloroacetic acid, acetone, and methanol. Show reagents and experimental conditions for the synthesis of Metolachlor from these four organic starting materials. Your syn thesis will most likely give a racemic mixture. The chiral catalyst used by Novartis for reduction in Step 2 gives \(80 \%\) enantiomeric excess of the \(S\) enantiomer.
See all solutions

Recommended explanations on Chemistry Textbooks

Making Measurements

Read Explanation

Chemical Reactions

Read Explanation

Chemical Analysis

Read Explanation

Nuclear Chemistry

Read Explanation

Inorganic Chemistry

Read Explanation

Ionic and Molecular Compounds

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free