Arrange the alkanes in each set in order of increasing boiling point. (a) 2-Methylbutane, 2,2-dimethylpropane, and pentane (b) 3,3-Dimethylheptane, 2,2,4-trimethylhexane, and nonane

Short Answer

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Question: Arrange the following alkanes in order of increasing boiling points: a) 2-methylbutane, 2,2-dimethylpropane, and pentane b) 3,3-dimethylheptane, 2,2,4-trimethylhexane, and nonane Answer: a) 2,2-dimethylpropane < 2-methylbutane < pentane b) 2,2,4-trimethylhexane < 3,3-dimethylheptane < nonane

Step by step solution

01

1. Identify the molecular structures

Draw the structures of 2-methylbutane, 2,2-dimethylpropane, and pentane: 2-Methylbutane: CH3 | CH3-CH-C-CH3 | CH3 2,2-Dimethylpropane: CH3 | CH3-C-CH3 | CH3 Pentane: CH3-CH2-CH2-CH2-CH3
02

2. Compare molecular size and branching

Compare the sizes and branching of the alkanes: 2-Methylbutane and pentane have 5 carbons each, while 2,2-dimethylpropane has 4 carbons. 2-Methylbutane is branched while pentane is unbranched and, therefore, has a larger surface area. 2,2-Dimethylpropane is the most branched and has the smallest surface area.
03

3. Arrange in order of increasing boiling points

Based on their molecular size and branching, we can arrange them in order of increasing boiling points: 2,2-dimethylpropane < 2-methylbutane < pentane #Set (b)#
04

1. Identify the molecular structures

Draw the structures of 3,3-dimethylheptane, 2,2,4-trimethylhexane, and nonane: 3,3-Dimethylheptane: CH3 | CH3-CH2-CH2-C-CH2-CH2-CH2-CH3 | CH3 2,2,4-Trimethylhexane: CH3 | CH3-CH2-CH2-C-CH2-CH2-CH3 | CH3 Nonane: CH3-CH2-CH2-CH2-CH2-CH2-CH2-CH2-CH3
05

2. Compare molecular size and branching

Compare the sizes and branching of the alkanes: 3,3-Dimethylheptane and 2,2,4-trimethylhexane both have 9 carbons while nonane has 9 carbons and an unbranched structure. 3,3-Dimethylheptane is slightly less branched compared to 2,2,4-trimethylhexane.
06

3. Arrange in order of increasing boiling points

Based on their molecular size and branching, we can arrange them in order of increasing boiling points: 2,2,4-trimethylhexane < 3,3-dimethylheptane < nonane

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Molecular Structure of Alkanes
Alkanes are organic compounds made up solely of carbon and hydrogen atoms arranged in a tree-like structure, meaning they don't contain any loops or rings. Their formula is generally written as CnH2n+2, where 'n' represents the number of carbon atoms. In their simplest form, the carbon atoms are connected by single bonds in a continuous, unbranched chain, with hydrogen atoms filling all other available bonds. This type of structure is known as a straight-chain or normal alkane.

However, alkanes can also have branches – when carbon chains diverge from the main carbon chain, creating a more complex molecular structure. This has significant effects on their physical properties, such as their boiling points. An important aspect of alkanes is that they are saturated hydrocarbons, meaning all available bonds are fully utilized (saturated) with hydrogen atoms.
Branching and Boiling Point Relationship
The boiling point of an alkane is influenced by the molecular structure, including the degree of branching. Branching tends to lower the boiling point of an alkane. This occurs because more branching reduces the surface area of the molecule, which in turn reduces the van der Waals forces (a type of intermolecular force) between the molecules.

These forces are weaker in highly branched alkanes than in unbranched ones since the latter can align more closely together, making them harder to separate—and thereby increasing their boiling points. Essentially, as branching increases, the molecules can't pack together as efficiently, resulting in a lower boiling point for the substance.

Effect of Surface Area

With a smaller surface area, the branched alkanes have fewer interactions with neighbouring molecules, leading to less energy required for the molecules to escape from the liquid to the gas phase.
Comparing Alkane Boiling Points
To compare the boiling points of alkanes, one must acknowledge both the length of the carbon chain and the degree of branching. Generally, a longer carbon chain means a higher boiling point due to increased van der Waals forces throughout the larger molecule. However, this trend is only true for alkanes with similar structures. When comparing different alkanes with varying degrees of branching, the trend can be counterintuitive.

For example, pentane, an unbranched alkane, has a higher boiling point than its isomers 2-methylbutane and 2,2-dimethylpropane, even though all have a similar molar mass. The key to understanding this lies in recognizing that 2,2-dimethylpropane, being the most branched, has the lowest boiling point among the three, while unbranched pentane has the highest.

Analyzing Molecular Arrangements

Therefore, analyzing the molecular arrangement provides insight into the energy necessary to overcome the attractive forces between the alkane molecules, which is a major contributing factor to the boiling points.

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Most popular questions from this chapter

Write structural formulas for the following alkanes and cycloalkanes. (a) \(2,2,4\)-Trimethylhexane (b) 2,2-Dimethylpropane (c) S-Ethyl-2,4,5-trimethyloctane (d) 5-Butyl-2,2-dimethylnonane (e) 4 -(1-Methylethyl) octane (f) 3,3-Dimethylpentane (g) trans-1,3-Dimethylcyclopentane (h) cis-1,2-Diethylcyclobutane

There are four cis, trans isomers of 2-isopropyl-5-methylcyclohexanol: CC1CCC(C(C)C)C(O)C1 2-Isopropyl-5-methylcyclohexanol (a) Using a planar hexagon representation for the cyclohexane ring, draw structural formulas for the four cis,trans isomers. (b) Draw the more stable chair conformation for each of your answers in part (a). (c) Of the four cis, trans isomers, which is the most stable? (Hint: If you answered this part correctly, you picked the isomer found in nature and given the name menthol.)

Draw structural formulas for all the following. (a) Alcohols with the molecular formula \(\mathrm{C}_{4} \mathrm{H}_{10} \mathrm{O}\) (b) Aldehydes with the molecular formula \(\mathrm{C}_{4} \mathrm{H}_{8} \mathrm{O}\) (c) Ketones with the molecular formula \(\mathrm{C}_{5} \mathrm{H}_{10} \mathrm{O}\) (d) Carboxylic acids with the molecular formula \(\mathrm{C}_{5} \mathrm{H}_{10} \mathrm{O}_{2}\)

Consider 1-bromopropane, \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{Br}\). (a) Draw a Newman projection for the conformation in which \(-\mathrm{CH}_{3}\) and \(-\mathrm{Br}\) are anti (dihedral angle \(180^{\circ}\) ). (b) Draw Newman projections for the conformations in which \(-\mathrm{CH}_{3}\) and \(-\mathrm{Br}\) are gauche (dihedral angles \(60^{\circ}\) and \(300^{\circ}\) ). (c) Which of these is the lowest energy conformation? (d) Which of these conformations, if any, are related by reflection?

For 1,2-dichloroethane: (a) Draw Newman projections for all eclipsed conformations formed by rotation from \(0^{\circ}\) to \(360^{\circ}\) about the carbon-carbon single bond. (b) Which eclipsed conformation (s) has (have) the lowest energy? Which has (have) the highest energy? (c) Which, if any, of these eclipsed conformations are related by reflection?

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