Account for the fact that \(p\)-nitrophenol \(\left(K_{\mathrm{a}} 7.0 \times 10^{-8}\right)\) is a stronger acid than phenol $$ \left(K_{\mathrm{a}} 1.1 \times 10^{-10}\right) $$

Short Answer

Expert verified
Question: Explain the factors that contribute to the increased acidity of p-nitrophenol as compared to phenol. Answer: The increased acidity of p-nitrophenol can be attributed to the presence of an electron-withdrawing nitro group in its structure, which stabilizes the negative charge on the phenoxide ion due to the inductive and resonance effects. This makes it easier for p-nitrophenol to lose a hydrogen ion, thus exhibiting a higher acidity compared to phenol.

Step by step solution

01

Recall the definition of Ka and acidity

The acidity constant, Ka, is a quantitative measure of an acid's strength. The higher the Ka value, the stronger the acid. This means that p-nitrophenol, with a Ka of \(7.0\times10^{-8}\), is a stronger acid than phenol, which has a Ka of \(1.1\times10^{-10}\).
02

Identify the difference in the chemical structure of both compounds

In order to analyze the cause behind the difference in acidity, we need to look at the structures of both compounds. p-nitrophenol has a nitro group (NO2) attached para to the hydroxyl group in the phenol molecule, while phenol only has a single hydroxyl group (OH) attached to the benzene ring.
03

Explain how the nitro group affects the acidic strength

The presence of the nitro group in p-nitrophenol can increase the compound's acidity due to the electron-withdrawing effect of the nitro group on the benzene ring. This effect stabilizes the negative charge on the oxygen atom of the phenoxide ion (conjugate base) after the phenol loses its H+ ion, making it easier for the phenol to lose the hydrogen ion and thus be more acidic. The presence of the nitro group also induces resonance effects, which further stabilize the negative charge on the oxygen atom. Overall, this results in p-nitrophenol being a stronger acid compared to phenol.
04

Conclusion

In summary, the difference in acidity between p-nitrophenol and phenol can be attributed to the presence of an electron-withdrawing nitro group in the p-nitrophenol molecule, which stabilizes the negative charge on the phenoxide ion due to the inductive and resonance effects, making it easier for p-nitrophenol to lose its hydrogen ion and demonstrate higher acidity. This is reflected by the higher Ka value of p-nitrophenol compared to phenol.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Account for the fact that water-insoluble carboxylic acids ( \(\mathrm{p} K_{\mathrm{a}} 4-5\) ) dissolve in \(10 \%\) aqueous sodium bicarbonate \((\mathrm{pH} 8.5)\) with the evolution of a gas but that waterinsoluble phenols ( \(\mathrm{p} K_{\mathrm{a}} 9.5-10.5\) ) do not dissolve in \(10 \%\) sodium bicarbonate.

Following is an equation for hydroperoxidation of cumene. Propose a radical chain mechanism for this reaction. Assume that initiation is by an unspecified radical, R'.

When warmed in dilute sulfuric acid, 1-phenyl-1,2-propanediol undergoes dehydration and rearrangement to give 2-phenylpropanal. (a) Propose a mechanism for this example of a pinacol rearrangement (Section 10.7). (b) Account for the fact that 2-phenylpropanal is formed rather than its constitutional isomer, 1-phenyl-1-propanone.

A finding that opened a route to \(\beta\)-blockers was the discovery that \(\beta\)-blocking activity is retained if an oxygen atom is interposed between the aromatic ring and the side chain. To see this difference, compare the structures of labetalol (Problem 22.55) and propranolol. Thus, alkylation of phenoxide ions can be used as a way to introduce this side chain. The first of this new class of drugs was propranolol. (a) Show how propanolol can be synthesized from 1-naphthol, epichlorohydrin (Section 11.10), and isopropylamine. (b) Is propranolol chiral? If so, which of the possible stereoisomers are formed in this synthesis?

The compound 2-hydroxypyridine, a derivative of pyridine, is in equilibrium with 2-pyridone. 2-Hydroxypyridine is aromatic. Does 2-pyridone have comparable aromatic character? Explain.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free