Chapter 21: Problem 32
Account for the fact that \(p\)-nitrophenol \(\left(K_{\mathrm{a}} 7.0 \times 10^{-8}\right)\) is a stronger acid than phenol $$ \left(K_{\mathrm{a}} 1.1 \times 10^{-10}\right) $$
Chapter 21: Problem 32
Account for the fact that \(p\)-nitrophenol \(\left(K_{\mathrm{a}} 7.0 \times 10^{-8}\right)\) is a stronger acid than phenol $$ \left(K_{\mathrm{a}} 1.1 \times 10^{-10}\right) $$
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Get started for freeAccount for the fact that water-insoluble carboxylic acids ( \(\mathrm{p} K_{\mathrm{a}} 4-5\) ) dissolve in \(10 \%\) aqueous sodium bicarbonate \((\mathrm{pH} 8.5)\) with the evolution of a gas but that waterinsoluble phenols ( \(\mathrm{p} K_{\mathrm{a}} 9.5-10.5\) ) do not dissolve in \(10 \%\) sodium bicarbonate.
Following is an equation for hydroperoxidation of cumene. Propose a radical chain mechanism for this reaction. Assume that initiation is by an unspecified radical, R'.
When warmed in dilute sulfuric acid, 1-phenyl-1,2-propanediol undergoes dehydration and rearrangement to give 2-phenylpropanal. (a) Propose a mechanism for this example of a pinacol rearrangement (Section 10.7). (b) Account for the fact that 2-phenylpropanal is formed rather than its constitutional isomer, 1-phenyl-1-propanone.
A finding that opened a route to \(\beta\)-blockers was the discovery that \(\beta\)-blocking activity is retained if an oxygen atom is interposed between the aromatic ring and the side chain. To see this difference, compare the structures of labetalol (Problem 22.55) and propranolol. Thus, alkylation of phenoxide ions can be used as a way to introduce this side chain. The first of this new class of drugs was propranolol. (a) Show how propanolol can be synthesized from 1-naphthol, epichlorohydrin (Section 11.10), and isopropylamine. (b) Is propranolol chiral? If so, which of the possible stereoisomers are formed in this synthesis?
The compound 2-hydroxypyridine, a derivative of pyridine, is in equilibrium with 2-pyridone. 2-Hydroxypyridine is aromatic. Does 2-pyridone have comparable aromatic character? Explain.
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