Draw a structural formula for each compound. (a) 1-Bromo-2-chloro-4-ethylbenzene (b) \(m\)-Nitrocumene (c) 4-Chloro- 1,2 -dimethylbenzene (d) 3,5 -Dinitrotoluene (e) \(2,4,6\)-Trinitrotoluene (f) \((2 S, 4 R)\)-4-Phenyl-2-pentanol (g) \(p\)-Cresol (h) Pentachlorophenol (i) 1-Phenylcyclopropanol (j) Triphenylmethane (k) Phenylethylene (styrene) (I) Benzyl bromide (m) 1-Phenyl-1-butyne (n) \((E)\)-3-Phenyl-2-propen-1-ol

Identify substituents and their positions on a benzene ring: one bromo group in position 1, one chloro group in position 2, and one ethyl group in position 4. Draw the benzene ring and add the substituents according to their positions in the name. Here is the structural formula for 1-Bromo-2-chloro-4-ethylbenzene: ``` Br Cl \ / |\ | -C- / C ```

Identify substituents and their positions on a benzene ring: one chloro group in position 4, one methyl group in position 1, and another methyl group in position 2. Draw the benzene ring and add the substituents according to their positions in the name. Here is the structural formula for 4-Chloro- 1,2 -dimethylbenzene: ``` Cl | C /|\/ C-C \/| C ```

Understand the name: (2S, 4R) are the stereochemical configurations at positions 2 and 4 of a pentane chain. Position 2 carries a hydroxyl group (OH), and position 4 carries a phenyl group (C6H5). Pentane has five carbons in a chain. Draw the pentane chain, add the substituents OH and phenyl group at positions 2 and 4, respectively, and mark the chiral centers with stereochemical configurations (S) and (R). Here is the structural formula for (2S, 4R)-4-Phenyl-2-pentanol: ``` C-Phenyl (at position 4, with R configuration) H | | C-H C-OH (at position 2, with S configuration) | | C-H | C-H | H ```

Understand the name: penta meaning five chloro groups attached to a phenol group, which is a benzene ring with a hydroxyl group (OH). Draw the benzene ring, add the hydroxyl group, and then add five chloro groups at the remaining carbon positions. Here is the structural formula for Pentachlorophenol: ``` Cl Cl \|/ --C--O-H / \ Cl Cl \/ C | Cl ```

Understand the name: phenylethylene or styrene is composed of a phenyl (C6H5) group attached to an ethylene (C=C) double bond. Draw the ethylene double bond and attach the phenyl group to one of the carbons in the ethylene. Here is the structural formula for Phenylethylene (styrene): ``` C/=C | C /|\ C--C |_| \| ```