Draw a structural formula for the form of each amino most prevalent at pH \(10.0\). (a) Leucine (b) Valine (c) Proline (d) Aspartic acid

Short Answer

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Question: Draw the structural formulas of Leucine, Valine, Proline, and Aspartic acid at pH 10.0.

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01

a) Leucine

First, let's examine Leucine's structure. Leucine has the following chemical formula: H\(_2\)N-CH- (CH\(_2\)CH\(_2\)CH)\(_2\)(CH\(_3\))_2\(. As the given pH is 10.0, the amino group (NH\)_2\() will accept a proton and become charged as NH\)_3^+\(, and the carboxyl group (COOH) will lose a proton and become charged as COO\)^-\(. Thus, the structural formula for Leucine at pH 10.0 is: H\)_3\(N\)^+\(-CH- (CH\)_2\(CH\)_2\(CH)\)_2\((CH\)_3\()_2\) -COO^-$.
02

b) Valine

Valine's chemical formula is H\(_2\)N-CH-CH\(_3\)-(CH\(_3\))\(_2\)(CH\(_3\)). Similar to Leucine, the amino group will accept a proton due to the given pH of 10.0, resulting in the charged form NH\(_3^+\). The carboxyl group will lose a proton and become charged as COO\(^-\). The corresponding structural formula for Valine is: H\(_3\)N\(^+\)-CH-CH\(_3\)-(CH\(_3\))\(_2\)(CH\(_3\)) -COO^-$.
03

c) Proline

For Proline, the chemical formula is H\(_2\)N-CH-(CH\(_2\))\(_3\)-NH. Due to the pH of 10.0, the amino group will accept a proton, and the carboxyl group will lose a proton. Thus, Proline's structural formula becomes H\(_3\)N\(^+\)-CH-(CH\(_2\))\(_3\)-NH -COO^-$.
04

d) Aspartic acid

Aspartic acid's chemical formula is H\(_2\)N-CH-CH\(_2\)-COOH. In this case, the amino group will accept a proton, and the carboxyl group will lose a proton, similar to the other amino acids. However, the side chain also contains a carboxyl group (COOH). Since the given pH is 10.0, this side chain carboxyl group will also lose a proton. The resulting structural formula for Aspartic acid is: H\(_3\)N\(^+\)-CH-CH\(_2\)-COO\(^-\) -COO^-$. You now have the structural formulas for Leucine, Valine, Proline, and Aspartic acid at pH 10.0!

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