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Chapter 3: Problem 11

Think about the helical coil of a telephone cord or a spiral binding and suppose that you view the spiral from one end and find that it is a left- handed twist. If you view the same spiral from the other end, is it a right- handed or left-handed twist?

Short Answer

Expert verified
Answer: Yes, the direction of the twist of a helical coil appears to change when viewed from the opposite end. A left-handed twist from one end will appear as a right-handed twist from the opposite end, due to the change in perspective.

Step by step solution

01

Understand the properties of helical coils

A helical coil is a spatial curve that follows the shape of a helix. The twist of a helical coil can be described as either left-handed (counterclockwise) or right-handed (clockwise) depending on the direction of curvature.
02

Visualize the coil from one end

First, let's assume the helical coil has a left-handed twist when viewed from one end. This means that, as you move along the coil from that end, it curves counterclockwise.
03

Visualize the coil from the opposite end

Now, we will view the helical coil from the other end. Since we are now looking at the coil from the opposite direction, the curvature will appear to be opposite to what it was from the first end.
04

Determine the twist from the opposite end

When we view the coil from the opposite end, the previously left-handed (counterclockwise) twist will now appear as a right-handed (clockwise) twist. This is because our perspective has changed, and we are now following the curvature of the coil in the opposite direction. In conclusion, if a helical coil appears to have a left-handed twist from one end, it will appear as a right-handed twist when viewed from the opposite end.

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Most popular questions from this chapter

One reason we can be sure that \(s p^{3}\)-hybridized carbon atoms are tetrahedral is the number of stereoisomers that can exist for different organic compounds. (a) How many stereoisomers are possible for \(\mathrm{CHCl}_{3}, \mathrm{CH}_{2} \mathrm{Cl}_{2}\), and \(\mathrm{CHClBrF}\) if the four bonds to carbon have a tetrahedral arrangement? (b) How many stereoisomers would be possible for each of these compounds if the four bonds to the carbon had a square planar geometry?

Assign priorities to the groups in each set. (a) \(-\mathrm{H}-\mathrm{CH}_{3}-\mathrm{OH}-\mathrm{CH}_{2} \mathrm{OH}\) (b) \(-\mathrm{CH}_{2} \mathrm{CH}=\mathrm{CH}_{2}-\mathrm{CH}=\mathrm{CH}_{2}-\mathrm{CH}_{3}-\mathrm{CH}_{2} \mathrm{COOH}\) (c) \(-\mathrm{CH}_{3}-\mathrm{H}-\mathrm{COO}^{-}-\mathrm{NH}_{3}{ }^{+}\) (d) \(-\mathrm{CH}_{3}-\mathrm{CH}_{2} \mathrm{SH}-\mathrm{NH}_{3}^{+}-\mathrm{CHO}\)

Which compounds contain chiral centers? (a) 2-Chloropentane (b) 3-Chloropentane (c) 3-Chloro-1-pentene (d) 1,2 -Dichloropropane

When oxaloacetic acid and acetyl-coenzyme A (acetyl-CoA) labeled with radioactive carbon-14 in position 2 are incubated with citrate synthase, an enzyme of the tricarboxylic acid cycle, only the following enantiomer of \(\left[2-{ }^{14} \mathrm{C}\right]\) citric acid is formed stereoselectively. Note that citric acid containing only \({ }^{19} \mathrm{C}\) is achiral. Assign an \(R\) or \(S\) configuration to this enantiomer of \(\left[2{ }^{14} \mathrm{C}\right]\) citric acid. Note: Carbon- 14 has a higher priority than carbon-12.

To the following statements, answer True or False and explain your answer. (a) All chiral centers are also stereocenters. (b) All stereocenters are also chiral centers. (c) All chiral molecules are optically active when pure. (d) All mixtures of chiral molecules are optically active. (e) To be optically active, a molecule must have a chiral center. (f) To be meso, a molecule must have at least two chiral centers.
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