Label the most acidic hydrogen in each molecule, and justify your choice by using appropriate \(\mathrm{p} K_{\mathrm{a}}\) values. (a) \(\mathrm{HOCH}_{2} \mathrm{CH}_{2} \mathrm{NH}_{2}\) (b) \(\mathrm{HSCH}_{2} \mathrm{CH}_{2} \mathrm{NH}_{2}\) (c) \(\mathrm{HOCH}_{2} \mathrm{CH}_{2} \mathrm{C} \equiv \mathrm{CH}\) (d) \(\mathrm{HOCCH}_{2} \mathrm{CH}_{2} \mathrm{SH}\) (e) \(\mathrm{CH}_{3} \mathrm{CHCOH}_{\mathrm{CH}}^{\mathrm{HO}}\) (f) \(\mathrm{H}_{3} \mathrm{NCH}_{2} \mathrm{CH}_{2} \|_{\mathrm{COH}}^{\mathrm{O}}\) (g) \(\mathrm{H}_{3} \mathrm{NCH}_{2} \mathrm{CH}_{2} \|_{\mathrm{CO}^{-}}\) (h) \(\mathrm{HSCH}_{2} \mathrm{CH}_{2} \mathrm{OH}\)

Short Answer

Expert verified
Question: Identify the most acidic hydrogen in each of the following molecules and provide values to justify your choice: (a) \(\mathrm{HOCH}_{2} \mathrm{CH}_{2} \mathrm{NH}_{2}\) (b) \(\mathrm{HSCH}_{2} \mathrm{CH}_{2} \mathrm{NH}_{2}\) (c) \(\mathrm{HOCH}_{2} \mathrm{CH}_{2} \mathrm{C} \equiv \mathrm{CH}\) (d) \(\mathrm{HOCCH}_{2} \mathrm{CH}_{2} \mathrm{SH}\) (e) \(\mathrm{CH}_{3} \mathrm{CHCOH}_{\mathrm{CH}}^{\mathrm{HO}}\) (f) \(\mathrm{H}_{3} \mathrm{NCH}_{2} \mathrm{CH}_{2}\|_{\mathrm{COH}}^{\mathrm{O}}\) (g) \(\mathrm{H}_{3} \mathrm{NCH}_{2} \mathrm{CH}_{2} \|_{\mathrm{CO}^{-}}\) (h) \(\mathrm{HSCH}_{2} \mathrm{CH}_{2} \mathrm{OH}\)

Step by step solution

01

Analyze the molecule and identify the acidic hydrogen

For each molecule, analyze the available hydrogen atoms and determine which one is the most acidic based on its location within the molecule. The hydrogen is more likely to be acidic if it is attached to a more electronegative atom.
02

Use appropriate values to justify our choice

Using pKa values, justify our choice of the most acidic hydrogen. Recall that a lower \(\mathrm{p} K_{\mathrm{a}}\) value denotes a stronger acid, so we'll be looking for the smallest pKa value associated with each molecule. (a) \(\mathrm{HOCH}_{2} \mathrm{CH}_{2} \mathrm{NH}_{2}\) - Most acidic H: \(\mathrm{H}\) on \(\mathrm{O}\) (alcohol), \(\mathrm{p} K_{\mathrm{a}} \approx 16\) (b) \(\mathrm{HSCH}_{2} \mathrm{CH}_{2} \mathrm{NH}_{2}\) - Most acidic H: \(\mathrm{H}\) on \(\mathrm{S}\) (thiol), \(\mathrm{p} K_{\mathrm{a}} \approx 10\) (c) \(\mathrm{HOCH}_{2} \mathrm{CH}_{2} \mathrm{C} \equiv \mathrm{CH}\) - Most acidic H: \(\mathrm{H}\) on \(\mathrm{O}\) (alcohol), \(\mathrm{p} K_{\mathrm{a}} \approx 16\) (d) \(\mathrm{HOCCH}_{2} \mathrm{CH}_{2} \mathrm{SH}\) - Most acidic H: \(\mathrm{H}\) on \(\mathrm{O}\) (carboxylic acid), \(\mathrm{p} K_{\mathrm{a}} \approx 4\) (e) \(\mathrm{CH}_{3} \mathrm{CHCOH}_{\mathrm{CH}}^{\mathrm{HO}}\) - Most acidic H: \(\mathrm{H}\) on \(\mathrm{O}\) (alcohol), \(\mathrm{p} K_{\mathrm{a}} \approx 16\) (f) \(\mathrm{H}_{3} \mathrm{NCH}_{2} \mathrm{CH}_{2}\|_{\mathrm{COH}}^{\mathrm{O}}\) - Most acidic H: \(\mathrm{H}\) on \(\mathrm{O}\) (carboxylic acid), \(\mathrm{p} K_{\mathrm{a}} \approx 4\) (g) \(\mathrm{H}_{3} \mathrm{NCH}_{2} \mathrm{CH}_{2} \|_{\mathrm{CO}^{-}}\) - Most acidic H: \(\mathrm{H}\) on \(\mathrm{N}\) (amine, as carboxylate is already deprotonated), \(\mathrm{p} K_{\mathrm{a}} \approx 38\) (h) \(\mathrm{HSCH}_{2} \mathrm{CH}_{2} \mathrm{OH}\) - Most acidic H: \(\mathrm{H}\) on \(\mathrm{S}\) (thiol), \(\mathrm{p} K_{\mathrm{a}} \approx 10\) In each case, the most acidic hydrogen has been identified and justified using appropriate \(\mathrm{p} K_{\mathrm{a}}\) values.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding pKa Values
pKa values are essential when it comes to understanding the acidity of different hydrogen atoms within a molecule. The pKa value essentially tells us how easily a hydrogen atom can be removed, with a lower pKa value indicating a stronger acid. In a way, you can think of the pKa as a 'password' that quantifies how tightly a proton is held by a molecule. The easier it is for a molecule to give up a proton (H+), the lower its pKa value is, and the stronger the acid.

For example, substances like carboxylic acids have relatively low pKa values (around 4-5), which signifies that they're quite acidic and can donate a proton with ease. On the other hand, compounds like alcohols and thiols have higher pKa values (around 16 and 10, respectively), implying they are less acidic.

It is important for students to remember that pKa values are not abstract numbers; they play a direct role in predicting the behavior of substances in various chemical reactions, such as esterification or acid-base equilibria. Knowing the pKa allows chemists to manipulate the reaction conditions to favor the formation of desired products.
Molecular Structure Analysis
Analyzing the molecular structure is crucial when identifying the most acidic hydrogen in a molecule. The acidity of a hydrogen atom depends on several factors, such as the electronegativity of the atom it is attached to, the stability of the resulting conjugate base, and the presence of resonance structures.

In acids, hydrogen is often attached to electronegative atoms like oxygen or sulfur. These electronegative atoms draw electron density away from the hydrogen, making it more prone to loss as a proton. For instance, in carboxylic acids, the additional oxygen atom provides resonance stabilization to the conjugate base, which makes the hydrogen more acidic.

In contrast, carbon-hydrogen bonds are generally less acidic because carbon is less electronegative. However, there are exceptions such as hydrogens attached to sp carbon atoms in alkynes, which are more acidic due to the increased s-character of the bond.

Understanding each functional group and the influence of molecular structure on acidity is a cornerstone of organic chemistry. It allows students to predict reaction mechanisms and understand why certain reactants are used in specific syntheses.
Acid Strength Comparison
Comparing the acid strength of different molecules is an integral skill in chemistry, closely linked to both the pKa values and molecular structure. Acid strength can inform us about a substance's reactivity, solubility, and even its biological activity.

When we compare acid strengths, we look at the pKa values and the molecular context that gives rise to such values. For instance, a hydrogen bonded to an oxygen in a carboxylic acid group will usually be more acidic than a hydrogen bonded to an oxygen in a simple alcohol group. This is due to the additional resonance stabilization of the carboxylate anion compared to the alkoxide anion.

To skillfully judge acid strength, students should also consider inductive effects and the overall stability of the conjugate base, which plays a significant role in determining acidity. A stable conjugate base, meaning the anion left behind after the acid has given up its proton, implies a strong acid. Integrating these concepts helps in creating a thorough understanding of acidic and basic properties in various chemical systems.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Calculate \(K_{\mathrm{eq}}\) for a reaction with \(\Delta G^{\circ}=-17.1 \mathrm{~kJ} / \mathrm{mol}(-4.09 \mathrm{kcal} / \mathrm{mol})\) at \(328 \mathrm{~K}\). Compare this value to the \(1 \times 10^{3}\) seen at \(298 \mathrm{~K}\).

What is the strongest base that can exist in liquid ammonia as a solvent?

For each equation, label the Lewis acid and the Lewis base. In addition, show all unshared pairs of electrons on the reacting atoms, and use curved arrows to show the flow of electrons in each reaction. (a) \(\mathrm{F}^{-}+\mathrm{BF}_{3} \longrightarrow \mathrm{BF}_{4}^{-}\) (b)

Answer True or False to the following statements about energy diagrams and reactions. (a) A reaction coordinate diagram is used to visualize the change in the internal energy of chemical structures that occurs during chemical reactions. (b) Thermodynamics is the study of the energies of structures that are represented by wells on reaction coordinate diagrams. (c) Kinetics is the study of the rates of chemical reactions. (d) One part of a reaction mechanism would be the understanding of which bonds break and form during a reaction. (e) Thermal reactions occur via collisions between molecules, and the more energy in those collisions the greater the rate of the reactions. (f) The enthalpy of a reaction is the sole determinant of whether it will or will not occur. (g) An exergonic reaction will always occur during the life span of the standard human being.

Benzoic acid, \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{COOH}\left(\mathrm{p} K_{\mathrm{a}} 4.19\right)\), is only slightly soluble in water, but its sodium salt, \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{COO}^{-} \mathrm{Na}^{+}\), is quite soluble in water. In which solution(s) will benzoic acid dissolve? (a) Aqueous \(\mathrm{NaOH}\) (b) Aqueous \(\mathrm{NaHCO}_{3}\) (c) Aqueous \(\mathrm{Na}_{2} \mathrm{CO}_{3}\)

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free