Propose a mechanism for the acid-catalyzed hydration of 1 -methylcyclohexene to give 1 -methylcyclohexanol. Which step in your mechanism is rate determining?

Short Answer

Expert verified
Answer: The rate-determining step in this reaction is Step 2, the protonation of the alkene (1-methylcyclohexene), leading to the formation of a carbocation intermediate. This step has the highest activation energy due to the formation of a relatively high-energy carbocation intermediate.

Step by step solution

01

Write down the overall reaction

First, we need to write down the overall reaction for the acid-catalyzed hydration of 1-methylcyclohexene. 1-methylcyclohexene + H2O -> 1-methylcyclohexanol Now let's break down the reaction into individual steps.
02

Protonation of the alkene

In the presence of an acid, the alkene (1-methylcyclohexene) will be protonated, leading to the formation of a carbocation intermediate: 1-methylcyclohexene + H+ -> 1-methylcyclohexyl cation Here, the double bond of the alkene picks up a proton from the acid, breaking the double bond and forming a carbocation.
03

Nucleophilic attack by water

Next, the carbocation will be attacked by a nucleophile, which in this case is water. The lone pair of electrons on the oxygen of the water molecule attacks the carbocation, creating a bond: 1-methylcyclohexyl cation + H2O -> protonated 1-methylcyclohexanol Now we have a protonated alcohol.
04

Deprotonation of the protonated alcohol

The final step involves the deprotonation of the protonated alcohol by another water molecule, which acts as a base: protonated 1-methylcyclohexanol + H2O -> 1-methylcyclohexanol + H3O+ As a result, we obtain the desired product, 1-methylcyclohexanol, and the hydronium ion (H3O+).
05

Identify the rate-determining step

To identify the rate-determining step, we need to find the slowest step in the reaction mechanism. This is typically determined by examining the activation energy (barrier to reaction) for each step. In our case, the protonation of the alkene (Step 2) creates a carbocation intermediate, which is relatively high in energy. Thus, this step is the slowest and rate-determining. The remaining two steps (nucleophilic attack and deprotonation) are faster and therefore not rate-determining.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Protonation of Alkene
The process where the double bond in an alkene molecule accepts a proton, H+, is known as protonation. In an acid-catalyzed hydration reaction, this is often the first and one of the most vital steps.

For clarification, let's visualize 1-methylcyclohexene as two carbon atoms connected by a double bond. When this molecule is introduced to an acid, like sulfuric acid, the highly electron-rich area of the double bond is attracted to the positively charged hydrogen atom (the proton). When the alkene 'grabs' this proton, the double bond 'breaks,' reallocating one of its electrons to form a new bond with the hydrogen. This results in the formation of a carbocation, a species with a positively charged carbon atom that is eager for further reactions.

This step is crucial because the stability of the carbocation formed affects the overall rate of the reaction. More stable carbocations form quicker and with less energy compared to their less stable counterparts. Therefore, certain alkenes with the ability to form more stable carbocations will undergo hydration more readily.
Nucleophilic Attack
Once the carbocation is formed by protonation, it's primed for the next step: the nucleophilic attack. A nucleophile is a molecule or ion that donates a pair of electrons to form a new chemical bond. In this context, water (H2O) acts as our nucleophile.

Water is considered a nucleophile because the oxygen atom holds a pair of non-bonding electrons. The carbocation created from the protonation is positively charged and thus electron-poor, making it very attractive to electron-rich species. The non-bonding electrons on water's oxygen atom quickly associate with the carbon atom in the carbocation, establishing a new carbon-oxygen bond. This reaction transforms the carbocation into a protonated alcohol, which is, in our example, a protonated 1-methylcyclohexanol.

This step is generally quite fast, as the reactive carbocation is highly willing to accept electrons from the water molecule, making the nucleophilic attack happen readily once the protonated intermediate is in place.
Rate-Determining Step
In a multi-step reaction, the rate-determining step (RDS), often referred to as the rate-limiting step, is the slowest phase that determines the speed at which the reaction overall proceeds. It is essentially the 'bottleneck' of the reaction mechanism.

Identifying the RDS is a bit like finding the slowest runner in a relay race. No matter how fast the other runners are, the race progresses at the pace of the slowest runner. In our hydration reaction, the step in which the carbocation is formed is usually the RDS because forming a high-energy, unstable intermediate (the carbocation) requires surmounting a significant energy barrier. This means that the formation of the carbocation from the alkene and the proton will most often be slower than the subsequent nucleophilic attack by water and final deprotonation steps.

Understanding the rate-determining step is critical when developing synthetic processes or studying reaction mechanisms. By knowing which step limits the reaction, chemists can modify conditions or reactant structures to optimize reaction rates and yields, ultimately guiding the efficiency of chemical processes.

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Most popular questions from this chapter

Draw the alternative chair conformations for the product formed by the addition of bromine to 4-tert-butylcyclohexene. The Gibbs free energy differences between equatorial and axial substituents on a cyclohexane ring are \(21 \mathrm{~kJ}\) ( \(4.9 \mathrm{kcal}) / \mathrm{mol}\) for tert-butyl and \(2.0-2.6 \mathrm{~kJ}(0.48-0.62 \mathrm{kcal}) / \mathrm{mol}\) for bromine. Estimate the relative percentages of the alternative chair conformations you drew in the first part of this problem.

Treating cyclohexene with \(\mathrm{HBr}\) in the presence of acetic acid gives bromocyclohexane \((85 \%)\) and cyclohexyl acetate \((15 \%)\).

Write structural formulas for the major organic product(s) formed by reaction of 1-methylcyclohexene with each oxidizing agent. (a) \(\mathrm{OsO}_{4} / \mathrm{H}_{2} \mathrm{O}_{2}\) (b) \(\mathrm{O}_{3}\) followed by \(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{~S}\)

Consider the following reaction. Cyclohexane-1, 4-dicarbaldehyde (a) Draw a structural formula for the compound with the molecular formula \(\mathrm{C}_{4} \mathrm{H}_{12-}\) (b) Do you predict the product to be the cis isomer, the trans isomer, or a mixture of cis and trans isomers? Explain. (c) Draw a suitable stereorepresentation for the more stable chair conformation of the dicarbaldehyde formed in this oxidation.

The 2-propenyl cation appears to be a primary carbocation, and yet it is considerably more stable than a \(1^{\circ}\) carbocation such as the 1 -propyl cation. $$ \begin{array}{lc} \mathrm{CH}_{2}=\mathrm{CH}-\mathrm{CH}_{2}^{+} & \mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{CH}_{2}^{+} \\ \text {2-Propenyl cation } & \text { 1-Propyl cation } \end{array} $$ How would you account for the differences in the stability of the two carbocation?

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