Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 7: Problem 32

Using your roadmap as a guide, show how to convert ethylene into 1-butene. All of the carbon atoms of the target molecule must be derived from ethylene. Show all intermediate molecules synthesized along the way.

Short Answer

Expert verified
Answer: The chemical process for converting ethylene (C2H4) into 1-butene (C4H8) involves the dimerization of two ethylene molecules, which results in the formation of 1-butene (C4H8).

Step by step solution

01

Dimerization of Ethylene

First, we need to increase the number of carbon atoms by joining two ethylene molecules. This reaction is called dimerization. C2H4 + C2H4 → C4H8 This reaction results in the formation of 1-butene. The whole process can be represented as follows: 1. Start with one ethylene molecule (C2H4) 2. Add another ethylene molecule (C2H4) 3. Perform a dimerization reaction, resulting in 1-butene (C4H8) Thus, we have successfully converted ethylene into 1-butene, with all carbon atoms derived from ethylene.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Hydration of 2-pentyne gives a mixture of two ketones, each with the molecular formula \(\mathrm{C}_{5} \mathrm{H}_{10} \mathrm{O}\). Propose structural formulas for these two ketones and for the enol from which each is derived.

Complete each acid-base reaction and predict whether the position of equilibrium lies toward the left or toward the right. (a) $\mathrm{CH}_{3} \mathrm{C} \equiv \mathrm{CH}+\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{O}^{-} \mathrm{Na}^{+} \underset{\mathrm{CH}_{3} \mathrm{CH}_{3} \mathrm{OH}}{\rightleftharpoons}$ (b) $\mathrm{CH}_{3} \mathrm{C} \equiv \mathrm{CCH}_{2} \mathrm{CH}_{2} \mathrm{OH}+\mathrm{Na}^{+} \mathrm{NH}_{2}{ }^{-} \underset{\mathrm{NH}_{3}(l)}{\rightleftharpoons}$ (c) $\mathrm{CH}_{3} \mathrm{C} \equiv \mathrm{C}^{-} \mathrm{Na}^{+}+\mathrm{CH}_{3} \mathrm{COH} \rightleftharpoons$ $$

Show how to prepare each compound from 1-heptene: (a) 1,2 -Dichloroheptane (b) 1-Heptyne (c) 1-Heptanol (d) 2-Octyne (e) cis-2-Octene (f) trans-2-Octene

Show reagents and experimental conditions to bring about the following transformations.

Show how to convert 9-octadecynoic acid to the following. (a) \((E)-9-\) Octadecenoic acid (eliadic acid) (b) (Z)-9-Octadecenoic acid (oleic acid) (c) 9,10 -Dihydroxyoctadecanoic acid (d) Octadecanoic acid (stearic acid)
See all solutions

Recommended explanations on Chemistry Textbooks

Chemistry Branches

Read Explanation

Kinetics

Read Explanation

Making Measurements

Read Explanation

Physical Chemistry

Read Explanation

Chemical Analysis

Read Explanation

Inorganic Chemistry

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free