When cis-4-chlorocyclohexanol is treated with sodium hydroxide in ethanol, it gives mainly the substitution product trans-1,4-cyclohexanediol (1). Under the same reaction conditions, trans-4-chlorocyclohexanol gives 3-cyclohexenol (2) and the bicyclic ether (3).

Short Answer

Expert verified
Answer: When cis-4-chlorocyclohexanol reacts with sodium hydroxide in ethanol, the main product is trans-1,4-cyclohexanediol. In the case of trans-4-chlorocyclohexanol, the products are 3-cyclohexenol and a bicyclic ether.

Step by step solution

01

Understanding the reagents and reaction conditions

Sodium hydroxide (NaOH) is a strong base, and ethanol is used as a solvent in this reaction. It's important to note that under these conditions, the nucleophilic substitution reaction will dominate over elimination reactions.
02

Identify the leaving group in the starting compounds

In both cis-4-chlorocyclohexanol and trans-4-chlorocyclohexanol, the chlorine atom is the leaving group because it is bonded to a carbon and can depart as a chloride ion (Cl-).
03

Identify the nucleophile in the reaction

Sodium hydroxide (NaOH) is the source of the nucleophile in this reaction: hydroxide ion (OH-). The hydroxide ion will replace the leaving group (chlorine) in the starting compounds.
04

Reaction of cis-4-chlorocyclohexanol with sodium hydroxide

When cis-4-chlorocyclohexanol reacts with sodium hydroxide, the hydroxide ion replaces the chlorine atom via an SN2 mechanism to form trans-1,4-cyclohexanediol (1). It is essential to remember that the SN2 mechanism leads to inversion of the stereochemistry at the substitution site.
05

Reaction of trans-4-chlorocyclohexanol with sodium hydroxide

The reaction of trans-4-chlorocyclohexanol with sodium hydroxide yields two products: 3-cyclohexenol (2) and the bicyclic ether (3). These products result from an elimination reaction instead of a substitution reaction (which occurred in the case of cis-4-chlorocyclohexanol). The hydroxide ion acts as a base, removing a neighboring hydrogen atom, leading to the elimination of chloride and formation of a double bond, yielding 3-cyclohexenol (2). A secondary reaction occurs to form the bicyclic ether (3) through intramolecular nucleophilic attack on the neighboring hydroxyl group. In conclusion, treating cis-4-chlorocyclohexanol with sodium hydroxide in ethanol results mainly in the substitution product trans-1,4-cyclohexanediol (1). However, under the same conditions, trans-4-chlorocyclohexanol produces 3-cyclohexenol (2) and the bicyclic ether (3). This indicates that the stereochemistry of the starting compounds plays a significant role in the reaction outcome.

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Most popular questions from this chapter

Suggest a product of the following reaction. HI is a very strong acid. $$ \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OCH}_{2} \mathrm{CH}_{3}+2 \mathrm{HI} \longrightarrow $$

Consider the following statements in reference to \(\mathrm{S}_{\mathrm{N}} 1, \mathrm{~S}_{\mathrm{N}} 2, \mathrm{E} 1\), and \(\mathrm{E} 2\) reactions of haloalkanes. To which mechanism (s), if any, does each statement apply? (a) Involves a carbocation intermediate. (b) Is first order in haloalkane and first order in nucleophile. (c) Involves inversion of configuration at the site of substitution. (d) Involves retention of configuration at the site of substitution. (e) Substitution at a stereocenter gives predominantly a racemic product. (f) Is first order in haloalkane and zero order in base. (g) Is first order in haloalkane and first order in base. (h) Is greatly accelerated in protic solvents of increasing polarity. (i) Rearrangements are common. (j) Order of reactivity of haloalkanes is \(3^{\circ}>2^{\circ}>1^{\circ}\). (k) Order of reactivity of haloalkanes is methyl \(>1^{\circ}>2^{\circ}>3^{\circ}\).

The reaction of 1-bromopropane and sodium hydroxide in ethanol occurs by an \(\mathrm{S}_{\mathrm{N}} 2\) mechanism. What happens to the rate of this reaction under the following conditions? (a) The concentration of \(\mathrm{NaOH}\) is doubled. (b) The concentrations of both \(\mathrm{NaOH}\) and 1-bromopropane are doubled. (c) The volume of the solution in which the reaction is carried out is doubled.

The following nucleophilic substitution occurs with rearrangement. Suggest a mechanism for formation of the observed product. If the starting material has the \(S\) configuration, what is the configuration of the stereocenter in the product?

Draw structural formulas of all chloroalkanes that undergo dehydrohalogenation when treated with KOH to give each alkene as the major product. For some parts, only one chloroalkane gives the desired alkene as the major product. For other parts, two chloroalkanes may work.

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