Rank the following acids in decreasing order of their acid strength. In each case, explain why the previous compound should be a stronger acid than the one that follows it.

Short Answer

Expert verified

Stronger electron-withdrawing groups stabilize the anion of the conjugate base more than weaker groups do, leading to stronger acids. Chlorine is more electronegative and a stronger withdrawing group than bromine, making chloropentanoic acid a stronger acid than bromopentanoic acid.

Step by step solution

01

     Step 1

Stronger electron-withdrawing groups stabilize the anion of the conjugate base more than weaker groups do, leading to stronger acids. Chlorine is more electronegative and a stronger withdrawing group than bromine, making chloropentanoic acid a stronger acid than bromopentanoic acid.

02

Step 2

Adding a chlorine atom to pentanoic acid increases its acidity, and the effect is larger if the chlorine atom is closer to the acidic group.

03

Step 3

In case of bromopentanoic acid, acidic effect is larger if the bromine atom is closer to the acidic group. Therefore 2-bromopentanoic acid is more acidic than 4-bromopentanoic acid.

04

Step 4

Multiple electron-withdrawing groups stabilize the conjugate base and increase the acidity more than a single group does. Therefore 2,2 dichloropentanoic acid is more acidic than 2-chloropentanoic acid.

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Most popular questions from this chapter

The following compounds can all react as acids.

  1. For each compound, show its conjugate base. Show any resonance forms if applicable.
  2. Rank the conjugate bases in the order you would predict, from most stable to least stable.
  3. Rank the original compounds in order from strongest acid to weakest acid.

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The following compounds can all react as acids.

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