Chapter 6: Q50P (page 330)
Give a mechanism to explain the two products formed in the following reaction.

Short Answer
The mechanism of the given reaction is as follows,



Chapter 6: Q50P (page 330)
Give a mechanism to explain the two products formed in the following reaction.

The mechanism of the given reaction is as follows,



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For each pair of compounds, predict which one has the higher molecular dipole moment, and explain your reasoning.
(a) ethyl chloride or ethyl iodide
(b) 1-bromopropane or cyclopropane
(c) cis-2,3-dibromobut-2-ene or trans-2,3-dibromobut-2-ene
(d) cis-1,2-dichlorocyclobutane or trans-1,3-dichlorocyclobutane.
Question: Show the products you expect when each compound reacts with NBS with light shining on the reaction.
d)
Triethyloxonium tetrafluoroborate, (CH3CH2)3O+ BF4−, is a solid with melting point 91–92°C. Show how this reagent can transfer an ethyl group to a nucleophile (Nuc:−) in an SN2 reaction. What is the leaving group? Why might this reagent be preferred to using an ethyl halide? (Consult Table 6-2.)
Predict the compound in each pair that will undergo the SN2 reaction faster.
(a.)
(b.)
(c.)
(d.)
(e.)
(f.)
Draw the structures of the following compounds.
(a)sec-butyl bromide
(b)isobutyl chloride
(c) 1,2-chloro-3-methylpentane
(d) 2,2,2-tribromoethanol
(e) trans-1-bromo-2-methylcyclohexane
(f) methylene bromide
(g) iodoform
(h) 1-bromo-1-isopropylcyclopentane
(i) tert-pentyl bromide
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