Question: Give IUPAC names for the following compounds.

a.

b.

c.

d.

e.

f.

Short Answer

Expert verified

Answer

a) 4-phenylpent-2-yne

b) (E)-3-methylhept-2-en-4-yne

c) 2,2,5-trimethylhept-3-yne

d) 4,4-dibromopent-2-yne

e) (S)-3-methylhex-4-yn-3-ol

f) but-2-yn-1-ylcyclopentane

Step by step solution

01

About IUPAC nomenclature

The rules governed by the International Union of Pure and Applied Chemistry to name the organic compounds systematically is IUPAC nomenclature. The naming depends on the name of the parent chain, substituents attached, configurations, etc.

02

Naming of the compound (a)

The parent chain is made up of five carbons. Thus, the word ‘pent’ is used in the prefix. The numbering is given in such a way that the triple bond gets the lowest possible number. The numbering is shown below.

Numbering of alkyne

The triple bond is at second carbon and the phenyl group is at fourth carbon. Thus, the IUPAC name of this compound is 4-phenylpent-2-yne.

03

Naming of compound (b)

The parent chain is made up of seven carbons. Thus, the word ‘hept’ is used in the prefix. The numbering is given in such a way that the double bond gets the lowest possible number. The numbering is shown below.

Numbering of alkyne

The double bond is present at the second carbon and the triple bond is present at the fourth carbon. There is one methyl group at the third carbon atom. The configuration at the double bond is E because the higher priority groups are on the opposite side of the double bond. Thus, the IUPAC name of the given compound is (E)-3-methylhept-2-en-4-yne.

04

Naming of compound (c)

The parent chain is made up of seven carbons. Thus, the word ‘hept’ is used in the prefix. The numbering is given in such a way that the triple bond gets the lowest possible number. The numbering is shown below.

Numbering of alkyne

The triple bond is present at the third carbon. There are two methyl groups at the second carbon atom and one methyl group at the fifth carbon atom. Thus, the IUPAC name of the given compound is 2,2,5-trimethylhept-3-yne.

05

Naming of compound (d)

The parent chain is made up of five carbons. Thus, the word ‘pent’ is used in the prefix. The numbering is given in such a way that the triple bond gets the lowest possible number. The numbering is shown below.

Numbering of alkyne

The triple bond is present at the second carbon atom. There are two bromo groups at the fourth carbon atom. Thus, the IUPAC name of the given compound is 4,4-dibromopent-2-yne.

06

Naming of compound (e)

The parent chain is made up of six carbons. Thus, the word ‘hex’ is used in the prefix. The numbering is given in such a way that the functional group (OH) gets the lowest possible number. The numbering is shown below.

Numbering of alkyne

The functional group OH is present at the third carbon and the methyl group is present at the third carbon atom. The triple bond is present at the fourth carbon atom. Thus, the IUPAC name of the given compound is 3-methylhex-4-yn-3-ol.

07

Naming of compound (f)

The parent chain is made up of four carbons. Thus, the word ‘but’ is used in the prefix. The numbering is given in such a way that the functional group cyclopentyl ring gets the lowest possible number. The numbering is shown below.

Numbering of alkyne

The cyclopentyl group is present at the first carbon and the triple bond is present at the second carbon. Thus, the IUPAC name of the given compound is 1-cyclopentylbut-2-yne.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

When compound Z is treated with ozone, followed by dimethyl sulfide and washing with water, the products are formic acid, 3-oxobutanoic acid, and hexanal.

Propose a structure for compound Z. What uncertainty is there in the structure you have proposed?

Question:Using cyclooctyne as your starting material, show how you would synthesize the following compounds. (Once you have shown how to synthesize a compound, you may use it as the starting material in any later parts of this problem.)

(a)cis-cyclooctene

(b)cyclooctane

(c)trans-1,2-dibromocyclooctane

(d)cyclooctanone

(e)1,1-dibromocyclooctane

(f)3-bromocyclooctene

(g)cyclooctane-1,2-dione

(h)

(i)

The following functional group interchange is a useful synthesis of aldehydes.

(a)What reagents were used in this chapter for this transformation? Give an example to illustrate this method.

(b)This functional group interchange can also be accomplished using the following sequence.

Propose mechanisms from these steps.

(c) Explain why a nucleophilic reagent such as ethoxide adds to an alkyne more easily than it adds to an alkene.

Question:Show how you would accomplish the following synthetic transformations. Show all intermediates.

(a)2,2-dibromobutane→but-1-yne

(b)2,2-dibromobutane→but-2-yne

(c)but-1-yne→oct-3-yne

(d)trans-hex-2-ene→hex-2-yne

(e)2,2-dibromohexane→hex-1-yne

(f)cyclodecyne→cis-cyclodecene

(g)cyclodecyne→trans-cyclodecene

(h)hex-1-yne→hexan-2-one, CH3COCH2CH2CH2CH3

(i)hex-1-yne→hexanal, CH3(CH2)4CHO

(j)trans-hex-2-ene→cis-hex-2-ene

Give common names for the following compounds.

(a)CH3CCCH2CH3 (b)PhCCH

(c) 3-methyloct-4-yne (d)(CH3)3CCCCH(CH3)CH2CH3

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free