Question: Show how you would synthesize each compound, beginning with acetylene and any necessary additional reagents.

(a) prop-2-yn-1-ol (propargyl alcohol)

(b) hept-2-yn-4-ol

(c) 2-phenylbut-3-yn-2-ol

(d) 3-methylhex-4-yn-3-ol

Short Answer

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Answer

(a)

(b)

(C)

(d)

Step by step solution

01

Acetylene

An unsaturated chemical compound in which two carbon atoms are connected through a triple bond with general formula CnH2n-2 is known as alkyne.

Acetylene is the first member of the alkyne homologous series having the chemical formula C2H2

02

Synthesis of given compounds beginning with acetylene and reagents

The abstraction of acetylenic hydrogen can obtain acetylide ions from terminal alkyne upon adding a strong base, i.e., sodium amide. This acetylide plays a vital role in acetylene chemistry.

(a) prop-2-yn-1-ol (propargyl alcohol)

The compound prop-2-yn-1-ol can be synthesized by adding sodium amide and formaldehyde to acetylene. The presence of a protic solvent is required.

(b) hept-2-yn-4-ol

The compound hept-2-yn-4-ol can be synthesized by adding sodium amide, methyl iodide, and butyraldehyde to acetylene.

(c) 2-phenylbut-3-yn-2-ol

The compound 2-phenylbut-3-yn-2-ol can be synthesized by adding sodium amide and acetophenone to acetylene.

(d) 3-methylhex-4-yn-3-ol

The compound 3-methylhex-4-yn-3-ol can be synthesized by adding sodium amide, methyl iodide and butan-2-one to acetylene

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Most popular questions from this chapter

Question: Predict the products of the following acid-base reactions, or indicate if no significant reaction would take place.

(a)H-C≡C-H+NaNH2(b)H-CC-H+CH3Li(c)H-CC-H+NaOCH3(d)H-CC-H+NaOH(e)H-CCNa++NaOH(f)H-CCNa++H2O(g)H-CCNa++H2C=CH2(h)H2C=CH2+NaNH2(i)CH3OH+NaNH2

The following functional group interchange is a useful synthesis of aldehydes.

(a)What reagents were used in this chapter for this transformation? Give an example to illustrate this method.

(b)This functional group interchange can also be accomplished using the following sequence.

Propose mechanisms from these steps.

(c) Explain why a nucleophilic reagent such as ethoxide adds to an alkyne more easily than it adds to an alkene.

Disiamylborane adds only once to alkynes by virtue of its two bulky secondary isoamyl groups. Disiamylborane is prepared by the reaction of BH3. THF with an alkene.

(a) Draw the structural formulas of the reagents and the products in the preparation of disiamylborane.

(b) Explain why the reaction in part (a) goes only as far as the dialkylborane. Why is Sia3B not formed?

Write structural formulas for the following compounds (includes both old- and new-style names).

(a) 2-octyne (b) ethyl isopentyl acetylene (c) ethynylbenzene

(d) cyclohexyl acetylene (e) 5-methyl-3-octyne (f) trans-3,5-dibromocyclodecyne

(g) 5,5-dibromo-4-phenylcyclooct-1-yne (h) (E)-6-ethyloct-2-en-4-yne

(i) 1,4-heptadiyne (j) vinylacetylene (k) (S)-3-methyl-1-penten-4-yne

Propose a mechanism for the reaction of pent-1-yne with HBr in the presence of peroxides. Show why anti-Markovnikov orientation results.

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