Chapter 24: Q17P. (page 1273)
Use resonance forms to show delocalization of the negative charge in Ruhemann’s purple anion.
Short Answer

Formation of Ruhemann’s purple anion

Resonance form of Ruhemann’s purple anion
Chapter 24: Q17P. (page 1273)
Use resonance forms to show delocalization of the negative charge in Ruhemann’s purple anion.

Formation of Ruhemann’s purple anion

Resonance form of Ruhemann’s purple anion
All the tools & learning materials you need for study success - in one app.
Get started for free
Draw the electrophoretic separation of Trp, Cys, and His at pH 6.0.
The herbicide glyphosate(Roundup) kills plants by inhibiting an enzyme needed for synthesis of phenylalanine. Deprived of phenylalanine, the plant cannot make the proteins it needs, and it gradually weakens and dies. Although a small amount of glyphosate is deadly to a plant, its human toxicity is quite low. Suggest why this powerful herbicide has little effect on humans.
Peptides often have functional groups other than free amino groups at the N terminus and other than carboxyl groups at the C terminus.
(a) A tetrapeptide is hydrolyzed by heating with 6 M, and the hydrolysate is found to contain Ala, Phe, Val, and Glu. When the hydrolysate is neutralized, the odor of ammonia is detected. Explain where this ammonia might have been incorporated in the original peptide.
(b) The tripeptide thyrotropic hormone releasing factor(TRF) has the full name pyroglutamylhistidylprolinamide. The structure appears here. Explain the functional groups at the N terminus and at the C terminus.

(c)On acidic hydrolysis, an unknown pentapeptide gives glycine, alanine, valine, leucine and isoleucine. No odor of ammonia is detected when the hydrolysate is neutralized. Reaction with phenyl isothiocyanate followed by mild hydrolysis gives nophenylthiohydantoin derivative. Incubation with carboxypeptidase has no effect. Explain these findings.
Although tryptophan contains a heterocyclic amine, it is considered a neutral amino acid. Explain why the indole nitrogen of trytophan is more weakly basic than one of the imidazole nitrogens of histidine.
Draw the resonance forms of a protonated guanidino group and explain why arginine has such a strongly basic isoelectric point.
What do you think about this solution?
We value your feedback to improve our textbook solutions.