(a) Explain how pyrrole is isoelectronic with the cyclopentadienyl anion.

(b) Specifically, what is the difference between the cyclopentadienyl anion and pyrrole?

(c) Draw resonance forms to show the charge distribution on the pyrrole structure

Short Answer

Expert verified

a)

Cyclopentadienyl anion Pyrrole ( 6π electrons

and aromatic)

6π electrons and aromatic

b) Cyclopentadienyl is acidic whereas pyrrole is basic in nature.

(c)

Resonance structure of pyrrole

Step by step solution

01

Step 1:Isoelectronic species

The molecule that has the same number of electrons as of the electrons present in the counter atom, those species are referred to as isoelectronic species. In these species, the electrons would be the same but different elements will be present.

02

Characteristics of cyclopentadienyl anion and pyrrole

a) The pyrrole is an aromatic five-membered heterocyclic with one nitrogen atom and two double bonds. although it may seem that pyrrole has only four pi electrons, the nitrogen atom has a lone pair of electrons.

The cyclopentadienyl anion is an aromatic five-membered ring, with two double bonds and a negative charge of lone pair of electrons. So, it also contains six pi electrons. Hence it is isoelectronic with cyclopentadienyl anion

Cyclopentadienyl anion Pyrrole ( 6π electrons and aromatic)

6π electrons and aromatic

b) These two compounds are aromatic compounds. The cyclopentadienyl is usually acidic because the loss of proton converts the non-aromatic diene to the aromatic cyclopentadienyl anion. The pyrrole has amiono group. So, it has a basic nature. The pyrrole has 4 pi electrons and the nitrogen atom has a lone pair of electrons. So, it has 6 pi electrons. The cyclopentadienyl anion has 4 pi electrons and the negatively charged of lone pairs of a methylene group. So, it also has 6 pi electrons.

The cyclopentadienyl anion does not have any hetero atom but pyrrole has a nitrogen atom (heteroatom).

c) The lone pair of electrons on the nitrogen atom undergoes resonance to form four resonance contributors. They are represented as:


Resonance structure of pyrrole

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Explain why each compound is aromatic, antiaromatic, or nonaromatic

(a) Isoxazole

(b) 1,3-thiazole

(c) Pyran

(d) Pyrylium ion

(e) γ - pyrone

(f) 1,2-Dihydropyridine

(g)Cytosine

(h)

One of the following compounds is much more stable than the other two. Classify each as aromatic, antiaromatic, or nonaromatic

(a)Methyl heptalene

(b) Methyl azulene


(c) Methyl pentalene


Question: The benzene ring alters the reactivity of a neighboring group in the benzylic position much as a double bond alters the reactivity of groups in the allylic position.

Benzylic cations, anions, and radicals are all more stable than simple alkyl intermediates.

  1. Use resonance forms to show the delocalization (over four carbon atoms) of the positive charge, unpaired electron, and negative charge of the benzyl cation, radical, and anion.
  2. Toulene reacts with bromine in the presence of light to give benzyl bromide. Propose a mechanism for this reaction.

    c. Which of the following reactions will have the faster rate and give the better yield? Use a drawing of the transition state to explain your answer.

Question: The benzene ring alters the reactivity of a neighboring group in the benzylic position much as a double bond alters the reactivity of groups in the allylic position.

Benzylic cations, anions, and radicals are all more stable than simple alkyl intermediates.

  1. Use resonance forms to show the delocalization (over four carbon atoms) of the positive charge, unpaired electron, and negative charge of the benzyl cation, radical, and anion.
  2. Toulene reacts with bromine in the presence of light to give benzyl bromide. Propose a mechanism for this reaction.

c. Which of the following reactions will have the faster rate and give the better yield? Use a drawing of the transition state to explain your answer.

The following hydrocarbon has an unusually large dipole moment. Explain how a large dipole moment might arise.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free