(a) Draw all the Kekulé structures of anthracene and phenanthrene.

(b) Propose mechanisms for the two additions shown.

(c) In Chapter 8, most of the additions of bromine to double bonds gave entirely anti stereochemistry. Explain why the addition to phenanthrene gives a mixture of syn andanti stereochemistry.

(d) When the product from (c) is heated, HBr is evolved, and 9-bromophenanthrene results. Propose a mechanism for this dehydrohalogenation.

Short Answer

Expert verified

a)

Resonance structure of anthracene and phenanthrene

(b)

The mechanismsm for addition in phenanthrene

The mechanism for addition in anthracene

(c)

Formtion of brominium ion

(d)

Formation of carbocation

Formation of 9-bromophenanthrene

Step by step solution

01

(a) Kekule structures of anthracene and phenanthrene

Kekule structures are commonly observed in aromatic compounds. Here carbon atoms are represented as two ends of a line and each binds is shown as a dash. Hydrogen atoms are not mentioned.

Resonance structure of anthracene and phenanthrene

02

(b) Mechanism for two addition in phenanthrene and anthracene 

The mechanism for addition in phenanthrene

(c)The addition of bromide to normal double bonds involve the intermediate bromonium ion. So the nucleophilic attack from the opposite side gives entirely anti stereochemistry.

Formtion of brominium ion

Anti stereochemistry is not followed when the carbonium ions are stabilized. Bromonium ion is not formed in these cases.

When the bromine electrophile attacks phenanthrene the resulting carbonium is highly stabilized because of more conjugation so the nucleophile can attack from either side to give the mixture of both cis and trans isomers.

Resonance stabilized carbonium ion

(d) When 9,10-dibromo phenanthrene is heated HBr is eliminated to form 9-Bromo phenanthrene. This is an elimination that follows first-order kinetics. This reaction takes place in a two-step way:

1:

Formation of carbocation

2.

Formation of 9-bromophenanthrene

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Most popular questions from this chapter

(a) Explain how pyrrole is isoelectronic with the cyclopentadienyl anion.

(b) Specifically, what is the difference between the cyclopentadienyl anion and pyrrole?

(c) Draw resonance forms to show the charge distribution on the pyrrole structure

(a) Draw the molecular orbitals for the cyclopropenyl case. H H H (Because there are three p orbitals, there must be three MOs: one all-bonding MO and one degenerate pair of MOs.)

(b) Draw an energy diagram for the cyclopropenyl MOs. (The polygon rule is helpful.) Label each MO as bonding, nonbonding, or antibonding, and add the nonbonding line. Notice that it goes through the approximate average of the MOs.

(c) Add electrons to your energy diagram to show the configuration of the cyclopropenyl cation and the cyclopropenyl anion. Which is aromatic and which is antiaromatic?

Classify the following compounds as aromatic, antiaromatic, or nonaromatic

(a)

(b)

(c)

(d)

When 3-chlorocyclopropene is treated with AgBF4, AgCl precipitates. The organic product can be obtained as a crystalline material, soluble in polar solvents such as nitromethane but insoluble in hexane. When the crystalline material is dissolved in nitromethane containing KCl, the original 3-chlorocyclopropene is regenerated. Determine the structure of the crystalline material, and write equations for its formation and its reaction with chloride ion

Question: For each NMR spectrum, propose a structure consistent with the spectrum and the additional information provided.

a. Elemental analysis shows the molecular formula to be C8H7OCl . The IR spectrum shows a moderate absorption at 1602 cm-1 and a strong absorption at 1690 cm-1 .

b. The mass spectrum shows a double molecular ion of ratio 1:1 at m/z 184 and 186.

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