After a series of Kiliani–Fischer syntheses on (+)-glyceraldehyde, an unknown sugar is isolated from the reaction mixture. The following experimental information is obtained:

(1) Molecular formula C6H12O6

(2) Undergoes mutarotation.

(3) Reacts with bromine water to give an aldonic acid.

(4) Reacts with HNO3 to give an optically active aldaric acid.

(5) Ruff degradation followed by HNO3 oxidation gives an optically inactive aldaric acid. (6) Two Ruff degradations followed by HNO3 oxidation give meso-tartaric acid.

(7) When the original sugar is treated with CH3I and Ag2O, a pentamethyl derivative is formed. Hydrolysis gives a tetramethyl derivative with a free hydroxy group on C5.

(a) Draw a Fischer projection for the open-chain form of this unknown sugar. Use Figure 23-3 to name the sugar.

(b) Draw the most stable conform

Short Answer

Expert verified

(a)

D-altrose

(b)

(2S,3R,4R) - 2,3,4,5,6 - pentahydroxyhexanal

Step by step solution

01

Kiliani- Fischer synthesis (lengthening of the carbon chain)

Adding one carbon atom to the aldehyde end of the aldose lengthens an aldose chain. The sugar chain is lengthened as a result of this process with a new carbon atom at C1 position and the aldehyde group (C1 position earlier) is now moved to C2 position. For determining the structure of existing sugars and also for synthesizing new sugars, Kiliani-Fischer synthesis is used.

02

Mutarotation

A spontaneous change in the specific rotation of a solution of an optically active compound is known as mutarotation. This implies that the two samples are different but in solution they form an equilibrium mixture. Sugars which are reducing can undergo mutarotation while non-reducing sugars cannot undergo mutarotation.

03

Bromine water oxidation of monosaccharides

Bromine water oxidises aldehyde group (-CHO) of an aldose into carboxylic acid (-COOH). Moreover, bromine water does not oxidize alcohols and ketoses. The product formed from bromine water oxidation is known as an aldonic acid.

04

Nitric acid oxidation of monosaccharides

Nitric acid (HNO3) is considered to be stronger oxidizing agent than bromine water since it can oxidize both aldehyde group and the terminal -CH2OH group of an aldose to carboxylic acid (-COOH)groups. The resulting dicarboxylic acid formed is known as aldaric acid.

05

Ruff degradation (shortening of the carbon chain)

Synthesis of new sugars and its structure can be known by a process known as Ruff degradation. The sugar chains are shortened in Ruff degradation. It is a two- step process which is given as below:

oxidation of aldose to aldonoic acid by bromine water (Br2/H2O) .

aldonic acid formed is treated with hydrogen peroxide (H2O2) and ferric sulfate Fe2(SO4)3, that oxidises the carboxyl group to carbon dioxide (CO2) and the resulting aldose is formed with one fewer carbon atom.

06

Meso compounds

Meso compounds are defined as those which contain two or more asymmetric centres that are optically inactive. They consist of internal plane of symmetry such that one half of the molecule forms the mirror image of the other half. Since the optical activity due to one half is counterbalanced by the optical activity of the other half, so meso compounds are optically inactive.

07

Formation of methyl ether

Hydroxy groups of sugar can be converted to methyl ethers by treating with methyl iodide (CH3I) and silver oxide (Ag2O) . CH3-I group can be polarised by silver oxide (Ag2O), which makes the methyl carbon more strongly electrophilic. Attack by the -OH group of carbohydrate is then followed by deprotonation which gives the ether.

08

Drawing the structure and writing its systematic name

(a)

D-altrose aldonic acid

D-altrose aldaric acid

D-altrose aldaric acid

The name of the unknown sugar is D-altrose

(b) The most stable conformation of the most stable cyclic hemiacetal form of this sugar ( D-altrose ) is (2S,3R,4R) - 2,3,4,5,6 - pentahydroxyhexanal.

(2S,3R,4R) - 2,3,4,5,6 - pentahydroxyhexanal.

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Most popular questions from this chapter

Draw the structure of the individual mutarotating α and β anomers of maltose.

a) Draw D-allose, the C3 epimer of glucose.

b) Draw D-talose, the C2 epimer of D-galactose.

c) Draw D-idose, the C3 epimer of D-talose. Now compare your answers with Figure 23-3.

d) Draw the C4 “epimer” of D-xylose. Notice that this “epimer” is actually an L-series sugar, and we have seen its enantiomer. Give the correct name for this L-series sugar.

Predict the products obtained when D-galactose reacts with each reagent.

(a) Br2 and H2O

(b) NaOH,H2O

(c)CH3OH, H+

(d) Ag(NH3)+2OH+

(e) H2, Ni

(f) excess Ac2O and pyridine

(g) excess CH3I ,Ag2O

(h) NaBH4

(i) Br2 , H2O then H2O2 and Fe2(SO4)3

(j) (1) KCN/HCN; (2) H2 Pd/BaSO4; (3) H3O+

(k)excess HIO4

An important protecting group developed specifically for polyhydroxy compounds like nucleosides is the tetraisopropyl-disiloxanyl group, abbreviated TIPDS, that can protect two alcohol groups in a molecule.

(a) The TIPDS group is somewhat hindered around the Siatoms by the isopropyl groups. Which OHis more likely to react first with TIPDS chloride? Show the product with the TIPDS group on one oxygen.

(b) Once the TIPDS group is attached at the first oxygen, it reaches around to the next closest oxygen. Show the final product with two oxygens protected.

(c) The unprotected hydroxy group can now undergo reactions without affecting the protected oxygens. Show the product after the protected nucleoside from (b) is treated with tosyl chloride and pyridine, followed by NaBr, ending with deprotection with Bu4NF.

(a) Show the product that results when fructose is treated with an excess of methyl iodide and silver oxide.

(b) Show what happens when the product of part (a) is hydrolyzed using dilute acid.

(c) What do the results of parts (a) and (b) imply about the hemiacetal structure of fructose?

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