(a) Which of the D-aldopentoses will give optically active aldaric acids on oxidation with HNO3 ?

(b) Which of the D-aldotetroses will give optically active aldaric acids on oxidation withHNO3 ?

(c) Sugar X is known to be a D-aldohexose. On oxidation with HNO3 , X gives an optically inactive aldaric acid. When X is degraded to an aldopentose, oxidation of the aldopentose gives an optically active aldaric acid. Determine the structure of X.

(d) Even though sugar X gives an optically inactive aldaric acid, the pentose formed by degradation gives an optically active aldaric acid. Does this finding contradict the principle that optically inactive reagents cannot form optically active products?

(e) Show what products results if the aldopentose formed from degradation of X is further degraded to an aldotetrose. DoesHNO3 oxidize this aldotetrose to an optically active aldaric acid?

Short Answer

Expert verified

(a) D - arabinose and D - lyxose

(b) D - threose

(c) D - galactose

(d)No, it does not contradict the principle since the aldaric acid formed from aldohexose is a meso compound.

(e)

D - lyxose D - threose aldaric acid

The aldaric acid formed is optically active.

Step by step solution

01

Nitric acid oxidation of monosaccharides

Nitric acid (HNO3) is considered to be stronger oxidizing agent than bromine water since it can oxidize both aldehyde group and the terminal -CH2OH group of an aldose to carboxylic acid (-COOH) groups. The resulting dicarboxylic acid formed is known as aldaric acid.

02

Meso compounds

Meso compounds are defined as those which contain two or more asymmetric centres that are optically inactive. They consist of internal plane of symmetry such that one half of the molecule forms the mirror image of the other half. Since the optical activity due to one half is counterbalanced by the optical activity of the other half, so meso compounds are optically inactive.

03

Ruff degradation (shortening of the carbon chain)

Synthesis of new sugars and its structure can be known by a process known as Ruff degradation. The sugar chains are shortened in Ruff degradation. It is a two- step process which is given as below:

(1) oxidation of aldose to aldonoic acid by bromine water (Br2/H2O).

(2) aldonic acid formed is treated with hydrogen peroxide (H2O2) and ferric sulfate Fe2(SO4)3, that oxidises the carboxyl group to carbon dioxide (CO2) and the resulting aldose is formed with one fewer carbon atom.

04

Explanation

(a) D - arabinose and D - lyxose gives optically active aldaric acids on oxidation with HNO3 .

D - arabinose

D - lyxose

(b) D - threose gives optically active aldaric acid on oxidation with HNO3 .

D - threose

(c) Sugar X is D - galactose

D - galactose

D - galactose

(d) No, it does not contradict the principle since the aldaric acid formed from aldohexose is a meso compound.

(e)

D - lyxose D - threose aldaric acid

The aldaric acid formed is optically active.

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Most popular questions from this chapter

Emil Fischer synthesized L-gulose, an unusual aldohexose that reduces to give D-glucitol. Suggest a structure for this L sugar, and show how L-gulose gives the same alditol as D-glucose. (Hint: D-Glucitol has -CH2OHgroups at both ends. Either of these primary alcohol groups might have come from reduction of an aldehyde.)

Draw and name the enantiomers of the sugars shown in Figure 23-2. Give the relative configuration (D or L) and the sign of the rotation in each case.

The relative configurations of the stereoisomers of tartaric acid were established by the following synthesis:

(1) D-(+)-glyceraldehydediastereomers A and B (separated)

(2) Hydrolysis of A and B using aqueous Ba(OH)2 gave C and D, respectively.

(3) HNO3 oxidation of C and D gave (-)-tartaric acid and meso-tartaric acid, respectively.

(a) You know the absolute configuration of D-(+)-glyceraldehyde, Use Fischer projections to show the absolute configurations of products A, B, C, and D.

(b) Show the absolute configurations of the three stereoisomers of tartaric acid: (+)-tartaric acid, (-)-tartaric acid, and meso-tartaric acid.

Question: Exposure to nitrous acid (see Section 19-16), sometimes found in cells, can convert cytosine to uracil.

  1. Propose a mechanism for this conversion.
  2. Explain how this conversion would be mutagenic upon replication.
  3. DNA generally includes thymine, rather than uracil(found in RNA). Based on this fact, explain why the nitrous acid-induced mutation of cytosine to uracil is more easily repaired in DNA than it is in RNA.

Draw the structure of the individual mutarotating α and β anomers of maltose.

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