Question: Show the products you expect when each compound reacts with NBS with light shining on the reaction.

b)

Short Answer

Expert verified

b)The product formed from the above compound when react with NBS

Step by step solution

01

Step 1:

The bromination reaction is the process by which one or more bromine atoms are added to a chemical. Halogination reaction includes bromination reactions. N-bromosuccinimide, also known as NBS (sourse of Br), is employed in this reaction as a reagent to aid in radical substitution.

A free radical is a molecule that lacks charge and has an unpaired electron. Free radicals are extremely reactive substances with a brief shelf life.

02

Step 2:

First, the reagent N-bromosuccinimide (NBS) that produces the bromine radical Br undergoes radical formation.

03

Step 3:

An allylic free radical is the end product of the formation of free radical in the alkene. The proposed mechanism to explain the observed products in the described reaction between an alkene and NBS.

The provided reactants result in the formation of two products. According to the Saytzeff rule, the allylic radical is quite stable and endocyclic double bond are significantly more stable than exocyclic double bonds.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Question: A carboxylic acid has two oxygen atoms, each with two nonbonding pairs of electrons.

  1. Draw the resonance forms of a carboxylic acid that is protonated on the hydroxy oxygen atom.
  2. Compare the resonance forms with those given previously for an acid protonated on the carbonyl oxygen atom.
  3. Explain why the carbonyl oxygen atom of a carboxylic acid is more basic than the hydroxy oxygen.

Question:

  1. The Key Mechanism for Fischer esterification omitted some important resonance forms of the intermediates shown in brackets. Complete the mechanism by drawing all the resonance forms of these two intermediates.
  2. Propose a mechanism for the acid-catalyzed reaction of acetic acid with ethanol to give ethyl acetate.
  3. The Principle of Microscopic Reversibility states that a forward reaction and a reverse reaction taking place under the same conditions (as in equilibrium) must follow the same reaction pathway in microscopic detail. The reverse of the Fischer esterification is the acid-catalyzed hydrolysis of an ester. Propose a mechanism for the acid-catalyzed hydrolysis of ethyl benzoate, PhCOOCH2CH3.

Show how you would accomplish the following syntheses. Some of these conversions may require more than one step.

(a) isopentyl alcohol isopentyl acetate (banana oil)

(b) 3-ethylpentanoic acid3-ethylpentanenitrile

(c) isobutylamineN-isobutylformamide

(d) ethyl acetate3-methylpentan-3-ol

(e) cyclohexylamineN-cyclohexylacetamide

(f) bromocyclohexanedicyclohexylmethano

(g)

(h)

Show how you would accomplish the following syntheses efficiently (you may use any necessary reagents).

(a)trans-1-bromobut-2-ene→trans-pent-3-enoic acid (two ways)

(b)hex-3-ene→propanoic acid

(c) but-2-enal→but-2-enoic acid

(d) hexanoic acid→hexanal

(e)

(f)

(g)

(h)

Question:An unknown compound gives a molecular ion of m/z 70 in the mass spectrum. It reacts with semicarbazide hydrochloride to give a crystalline derivative, but it gives a negative Tollens test. The NMR and IR spectra follow. Propose a structure for this compound, and give peak assignments to account for the absorptions in the spectra. Explain why the signal at 1790 cm-1 in the IR spectrum appears at an unusual frequency.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free