Predict the major form of each compound when it is dissolved in pure water. To do this, you will need to estimate values for the compounds in (a), (b), and (c) based on similar compounds shown in Appendix 4. Values for the compound in (d) are given. Explain the differences, including why the values in part (d) are so different from the others.

(a) The name of the given compound is 2-(4-(aminomethyl) phenyl)acetic acid.There is one group with the COOH group attached to the benzene ring. At the para position, group is present.

The value is 4.7 for acetic acid. The product formation is favorable at equilibrium condition. There will be a difference of 6 value.

There will be the formation of an ion called 2-(4-(ammoniomethyl)phenyl)acetate. In this compound, there are three hydrogens attached to nitrogen and one positive charge on nitrogen. There is one negative charge on the carboxyl group.

(b) The value is 4.31 for acetic acid. The product formation is favorable at equilibrium conditions. The formed product is major at equilibrium condition.

There will be the formation of an ion called 2-(4-aminophenyl)acetate. In this compound, there are three hydrogens attached to nitrogen and one positive charge on nitrogen. There is one negative charge on the carboxyl group.

(c) The value is 4.2 for benzoic acid. The product formation is favorable at equilibrium conditions. The formed product is major at equilibrium condition.

There will be the formation of an ion called 4-metheyliumylbenzoate, ammonia salt. In this compound, there are three hydrogens attached to nitrogen and one positive charge on nitrogen.

There is one negative charge on the carboxyl group.

The value is 4.9 for benzoic acid. The product formation is favorable at equilibrium conditions. The formed product is major at equilibrium condition.

There will be the formation of an ion called 4-ammoniobenzoate. In this compound, there are three hydrogens attached to nitrogen and one positive charge on nitrogen. There is one negative charge on the carboxyl group.