Question: Oxidation of primary alcohol to an aldehyde usually gives some over-oxidation to the carboxylic acid. Assume you have used PCC to oxidize pentan-1-ol to pentanal.

  1. Show how you would use acid-base extraction to purify the pentanal.
  2. Which of the expected impurities cannot be removed from pentanal by acid-base extractions? How would you remove this impurity?

Short Answer

Expert verified

Answer

  1. An acid-base extraction to purify the pentanal is given below.


(b) Pentan-1-ol cannot be removed from pentanal by acid-base extraction. Instead, it can be removed by the distillation method.

Step by step solution

01

Acid-base extractions

A complex mixture is converted into organic acids, organic bases, and other molecules in acid-base extraction.Two different layers are formed: one is organic, and the other is an aqueous layer.

02

Acid-base extraction to purify the pentanal

A mixture of pentanal, pentanoic acid, pentan-1-ol, pyridine, and CrO3 is shaken with ether and water. The compounds soluble in the ether are pentanal, pentanoic acid, pentan-1-ol, and pyridine; the compounds soluble in water are pyridine and CrO3. Pyridine is soluble in both water and ether.

When pentanal, pentanoic acid, pentan-1-ol, and pyridine are shaken with aq. NaOH, pentanoic acid converts into CH3CH2CH2CH2COO-Na+; the rest remains the same.

Now, pentanal, pentan-1-ol, and pyridine are shaken with aq. HCl; pyridinium cation is formed; pentanal and pentan-1-ol remain the same. After evaporating ether and then distilling, two pure compounds, pentanal and pentan-1-ol, are formed.

Acid-base extraction to purify the pentanal

03

Distillation 

Distillation is one of the separation methods used for separating liquids by converting liquid into vapors, and then again, it is condensed into a liquid form. It involves different boiling points of liquids.

04

Removal of impurity 

(b) Pentan-1-ol cannot be removed from pentanal in acid-base extraction. So, these two can be separated by the process of distillation. The boiling point for pentan-1-ol is higher than pentanal because of hydrogen bonding.

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Most popular questions from this chapter

Question: A carboxylic acid has two oxygen atoms, each with two nonbonding pairs of electrons.

  1. Draw the resonance forms of a carboxylic acid that is protonated on the hydroxy oxygen atom.
  2. Compare the resonance forms with those given previously for an acid protonated on the carbonyl oxygen atom.
  3. Explain why the carbonyl oxygen atom of a carboxylic acid is more basic than the hydroxy oxygen.

Phenols (pKa≈ 10) are more acidic than other alcohols, so they are easily deprotonated by sodium hydroxide or potassium hydroxide. The anions of phenols (phenoxide ions) can be used in the Williamson ether synthesis, especially with very reactive alkylating reagents such as dimethyl sulfate. Using phenol, dimethyl sulfate, and other necessary reagents, show how you would synthesize methyl phenyl ether.

In each case, show how you would synthesize the chloride, bromide, and iodide from the corresponding alcohol.

(a) 1-halopropane (halo = chloro, bromo, iodo)

(b)1-halo-2-methylcyclopentane

(c)1-halo-1,3-dimethylcyclohexane

(d)2-halo-1,3-dimethylcyclohexane

Show how you would accomplish the following syntheses. Some of these conversions may require more than one step.

(a) isopentyl alcohol isopentyl acetate (banana oil)

(b) 3-ethylpentanoic acid3-ethylpentanenitrile

(c) isobutylamineN-isobutylformamide

(d) ethyl acetate3-methylpentan-3-ol

(e) cyclohexylamineN-cyclohexylacetamide

(f) bromocyclohexanedicyclohexylmethano

(g)

(h)

Question:An unknown compound gives a molecular ion of m/z 70 in the mass spectrum. It reacts with semicarbazide hydrochloride to give a crystalline derivative, but it gives a negative Tollens test. The NMR and IR spectra follow. Propose a structure for this compound, and give peak assignments to account for the absorptions in the spectra. Explain why the signal at 1790 cm-1 in the IR spectrum appears at an unusual frequency.

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