Question: When N-bromosuccinimide is added to hex-1-ene in $CC{l}_4$and a sunlamp is shone on the mixture, three products result.

1. Give the structures of these three products.
2. Propose a mechanism that accounts for the formation of these three products.

Radical reactions involve three steps—initiation (generation of free radical), propagation (free radical combines with hydrogen), and termination (two radicals react in such a way that the chain no longer propagates).In the last step, we get the products.

(b)In the first step, when NBS reacts with HBr, it generates a low concentration of $B{r}_2$.

Generation of low concentration of bromine radicals

Then the initiation step follows, where the two bromine radicals are formed.

Initiation step

In the propagation step, abstraction of hydrogen takes place and generates allylic radical. The radical will be a mixture of cis and trans.

The mechanism for the formation of three products