There are two ways of making 2-ethoxyoctane from octan-2-ol using the Williamson ether synthesis. When pure (-) -octan-2-ol of specific rotation -8.240is treated with sodium metal and then ethyl iodide, the product is 2-ethoxyoctane with a specific rotation of -15.60. When pure (-) -octan-2-ol is treated with tosyl chloride and pyridine and then with sodium ethoxide, the product is also 2-ethoxyoctane. Predict the rotation of the 2-ethoxyoctane made using the tosylation/sodium ethoxide procedure, and propose a detailed mechanism to support your prediction.

Short Answer

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The most reliable and versatile method for synthesis of ethers is given by Williamson method. In this method,SN2 attack of an alkoxide ion takes place on an unhindered primary alkyl halide or tosylate. The yield is poor if secondary alkyl halide is used. The alkoxide is generally made by adding Na, K,or NaH to the alcohol.

general form of Williamson ether synthesis

Step by step solution

01

Williamson ether synthesis

The most reliable and versatile method for synthesis of ethers is given by Williamson method. In this method,SN2 attack of an alkoxide ion takes place on an unhindered primary alkyl halide or tosylate. The yield is poor if secondary alkyl halide is used. The alkoxide is generally made by adding Na, K,or NaH to the alcohol.

general form of Williamson ether synthesis

02

Mechanism

When pure (-)-octan-2-ol of specific rotation -8.240 undergoes treatment with sodium metal and then ethyl iodide forms 2-ethoxyoctane with a specific rotation of -15.60.

formation of (R)-2-ethoxyoctane from (-)-octan-2-ol

Again, when pure (-)-octan-2-ol undergoes treatment with tosyl chloride and pyridine and then with sodium ethoxide also forms 2-ethoxyoctane.

formation of (S)-2-ethoxyoctane from (-)-octan-2-ol

The product formed from the second reaction is (S)-2-ethoxyoctane. (S)-2-ethoxyoctane has the same value of specific rotation as its enantiomer but with opposite sign, (+15.60).

SN2reaction showing inversion in configuration

This is a SN2 reaction where inversion of configuration takes place. Nucleophile attacks from the opposite side of the leaving group to form (S)-2-ethoxyoctane.

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Most popular questions from this chapter

Show how you would use the Williamson ether synthesis to prepare the following ethers. You may use any alcohols or phenols as your organic starting materials.

  1. Cyclohexyl propyl ether
  2. Isopropyl methyl ether
  3. 1-methoxy-4-nitrobenzene
  4. Ethyl n-propyl ether (two ways)
  5. Benzyl tert-butyl ether (benzyl =Ph-CH2-)

Show how you would accomplish the following transformations. Some of these examples require more than one step.

Which of the following ethers can be formed in good yield by condensation of the corresponding alcohols? For those that cannot be formed by condensation, suggest an alternative method that will work.

(a) dibutyl  ether

(b) ethyl  n-propyl  ether

(c) di-sec-butyl  ether

Question: (a) Predict the values of m/zand the structures of the most abundant fragments you would observe in the mass spectrum of di-n-propyl-ether.

(b) Give logical fragmentations to account for the following ions observed in the mass spectrum of 2-methoxypentane: 102,87,71,59,31.

Question. The 2001 Nobel Prize in Chemistry was awarded to three organic chemists who have developed methods for catalytic asymmetric synthesis. An asymmetric (or enantioselective) synthesis is one that converts an achiral starting material into mostly one enantiomer of a chiral product. K. Barry Sharpless (The Scripps Research Institute) developed an asymmetric epoxidation of allylic alcohols that gives excellent chemical yields and greater than 90% enantiomeric excess.

The Sharpless epoxidation uses tert-butyl hydroperoxide, titanium(IV) isopropoxide, and a dialkyl tartarate ester as the reagents. The following epoxidation of geraniol is typical.

  1. Which of these reagents is most likely to be the actual oxidizing agent? That is, which reagent is reduced in the reaction? What is the likely function of the other reagents?
  2. When achiral reagents react to give a chiral product, that product is normally formed as a racemic mixture of enantiomers. How can the Sharpless epoxidation give just one nearly pure enantiomer of the product?
  3. Draw the other enantiomer of the product. What reagents would you use if you wanted to epoxidize geraniol to give this other enantiomer?
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