Propose a Williamson synthesis of 3-butoxy-1,1-dimethylcyclohexane from 3,3-dimethyl-cyclohexanol and butan-1-ol.

Short Answer

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When Butan-1-ol reacts with tosyl chloride in the presence of pyridine. it gets converted into butyl tosylate in the first step. Pyridine acts as a base here and it abstracts the proton of the hydroxyl group forming oxygen anion which attacks on the tosyl group of tosyl chloride and as a result, chloride ion leaves as a leaving group.

Reaction of butan-1-ol with tosyl chloride

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01

Reaction of butan-1-ol with tosyl chloride

When Butan-1-ol reacts with tosyl chloride in the presence of pyridine. it gets converted into butyl tosylate in the first step. Pyridine acts as a base here and it abstracts the proton of the hydroxyl group forming oxygen anion which attacks on the tosyl group of tosyl chloride and as a result, chloride ion leaves as a leaving group.

Reaction of butan-1-ol with tosyl chloride

02

Williamson ether synthesis

Williamson ether synthesis works best when the nucleophile attacks at primary or methyl carbon. In the next step, when 3,3-dimethyl-cyclohexanol reacts with sodium, it forms sodium salt of 3,3-dimethyl cyclohexanol which then reacts with butyl tosylate (which was prepared in first step) and forms 3-butoxy-1,1-dimethylcyclohexane (which is our required product).

Williamson ether synthesis

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Most popular questions from this chapter

There are two ways of making 2-ethoxyoctane from octan-2-ol using the Williamson ether synthesis. When pure (-) -octan-2-ol of specific rotation -8.240is treated with sodium metal and then ethyl iodide, the product is 2-ethoxyoctane with a specific rotation of -15.60. When pure (-) -octan-2-ol is treated with tosyl chloride and pyridine and then with sodium ethoxide, the product is also 2-ethoxyoctane. Predict the rotation of the 2-ethoxyoctane made using the tosylation/sodium ethoxide procedure, and propose a detailed mechanism to support your prediction.

Question. Give the structures of intermediates A through H in the following synthesis of trans-1-cyclohexyl-2-methoxycyclohexane.

Question. The following reaction resembles the acid-catalyzed cyclization of squalene oxide. Propose a mechanism for this reaction.

Question. The 2001 Nobel Prize in Chemistry was awarded to three organic chemists who have developed methods for catalytic asymmetric synthesis. An asymmetric (or enantioselective) synthesis is one that converts an achiral starting material into mostly one enantiomer of a chiral product. K. Barry Sharpless (The Scripps Research Institute) developed an asymmetric epoxidation of allylic alcohols that gives excellent chemical yields and greater than 90% enantiomeric excess.

The Sharpless epoxidation uses tert-butyl hydroperoxide, titanium(IV) isopropoxide, and a dialkyl tartarate ester as the reagents. The following epoxidation of geraniol is typical.

  1. Which of these reagents is most likely to be the actual oxidizing agent? That is, which reagent is reduced in the reaction? What is the likely function of the other reagents?
  2. When achiral reagents react to give a chiral product, that product is normally formed as a racemic mixture of enantiomers. How can the Sharpless epoxidation give just one nearly pure enantiomer of the product?
  3. Draw the other enantiomer of the product. What reagents would you use if you wanted to epoxidize geraniol to give this other enantiomer?

Question. (a) Show how you would synthesize the pure (R) enantiomer of 2-pentyl methyl sulfide, starting with pure (R)-pentan-2-ol and any reagents you need.

(b) Show how you would synthesize the pure (S) enantiomer of the product, still starting with (R)-pentan-2-ol and any reagents you need.

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