1. Outline the syntheses indicated in Solved Problem 18-2, beginning with aldehydes and alkyl halides.
  2. Both of these syntheses of 1-phenylbuta-1,3-diene form the central double bond. Show how you would synthesize this target molecule by forming the terminal double bond.

Short Answer

Expert verified

The given alkene forms a four-membered transition state on reaction with triphenyl phosphine and butyl lithium which is used as base, and then on simultaneous bond-breaking and forming, we get the product in which negative charge is on carbon and positive charge on phosphorous, and in the next step, this negatively charged carbon or carbanion attacks on the carbonyl carbon of aldehyde, forming the alkene product with two double bonds not in conjugation.

The product formation can also occur starting from alkyl halide as the reactant, and using same reagents such as triphenyl phosphine and butyl lithium as base. Butyl lithium abstracts the proton from alkyl carbon forming witting ylide, and using different aldehyde, we can form the same product. Carbanion of wittig ylide attacks at carbonyl carbon of aldehyde forming the required product.

Formation of the alkene product

Step by step solution

01

Explanation of part (a):

The given alkene forms a four-membered transition state on reaction with triphenyl phosphine and butyl lithium which is used as base, and then on simultaneous bond-breaking and forming, we get the product in which negative charge is on carbon and positive charge on phosphorous, and in the next step, this negatively charged carbon or carbanion attacks on the carbonyl carbon of aldehyde, forming the alkene product with two double bonds not in conjugation.

The product formation can also occur starting from alkyl halide as the reactant, and using same reagents such as triphenyl phosphine and butyl lithium as base. Butyl lithium abstracts the proton from alkyl carbon forming witting ylide, and using different aldehyde, we can form the same product. Carbanion of wittig ylide attacks at carbonyl carbon of aldehyde forming the required product.

Formation of the alkene product

02

Explanation of part (b):

The given alkene forms a four-membered transition state on reaction with triphenyl phosphine and butyl lithium which is used as base, and then on simultaneous bond-breaking and forming, we get the product in which negative charge is on carbon and positive charge on phosphorous, and in the next step, this negatively charged carbon or carbanion attacks on the carbonyl carbon of aldehyde, forming the alkene product with two double bonds not in conjugation.

The product formation can also occur starting from alkyl halide as the reactant, and using same reagents such as triphenyl phosphine and butyl lithium as base. Butyl lithium abstracts the proton from alkyl carbon forming witting ylide, and using different aldehyde, we can form the same product. Carbanion of wittig ylide attacks at carbonyl carbon of aldehyde forming the required product, that is, 1-phenyl-buta-1,3-diene.

Formation of 1-phenyl-buta-1,3-diene

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Most popular questions from this chapter

Show how you would accomplish the following syntheses efficiently and in good yield. You may use any necessary reagents.

(a)acetaldehydelacticacid,CH3CH(OH)COOH

(b)

(c)

(d)

(e)

(f)

(g)

Propose a mechanism for both parts of the Wolff-Kishner reduction of cyclohexanone: the formation of the hydrazone, and then the base catalyzed reduction with evolution of nitrogen gas.

Predict the products formed when cyclopentanecarbaldehyde reacts with the following reagents.

(a) PhMgBr, then H3O+

(b) Tollens reagent

(c) semicarbazide and weak acid

(d) excess ethanol and acid

(e) propane-1-3-diol, H+

(f) zinc amalgam and dilute hydrochloric acid

Question. (a) Simple aminoacetals hydrolyze quickly and easily in dilute acid. Propose a mechanism for hydrolysis of the following aminoacetal:

(b) The nucleosides that make up DNA have heterocyclic rings linked to deoxyribose by an aminoacetal functional group. Point out the aminoacetal linkages in deoxycytidine and deoxyadenosine.

(c) The stability of our genetic code depends on the stability of DNA. We are fortunate that the aminoacetal linkages of DNA are not easily cleaved. Show why your mechanism for part (a) does not work so well with deoxycytidine and deoxyadenosine.

Like other strong nucleophiles, triphenylphosphine attacks and opens epoxides. The initial product (a betaine) quickly cyclizes to an oxaphosphetane that collapses alkene and triphenylphospine oxide.

  1. Show each step in the reaction of trans-2,3-epoxybutane with triphenylphospine to give but-2-ene. What is the stereochemistry of the double bond in the product?
  2. Show how this sequence might be used to convert cis-cyclooctene to trans-cyclooctene.
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