Give the structures of the intermediates and products V through Z.

Alcohol that is made up of a five-membered ring with one OH group is cyclopentanol. This compound is colorless and exists in the liquid state at room temperature.

The reaction of cyclopentanol with PB₃ gives bromocyclopentane. Therefore, product W is bromocyclopentane. When bromocyclopentane is treated with magnesium in the presence of ether, cyclopentylmagnesium bromide is obtained. Therefore, product X is cyclopentylmagnesium bromide. The reaction of cyclopentanol with Na₂Cr₂O₇and H₂SO₄gives cyclopentanone. Thus, product V is cyclopentanone.

The cyclopentylmagnesium bromide reacts with cyclopentanone to give [1,1'-bi(cyclopentan)]-1-ol. Therefore, the product Y is [1,1'-bi(cyclopentan)]-1-ol. The reaction of [1,1'-bi(cyclopentan)]-1-ol with acetyl chloride gives [1,1'-bi(cyclopentan)]-1-yl acetate. Thus, the product Z is [1,1'-bi(cyclopentan)]-1-yl acetate.

The chemical reaction is shown below.