Alcohols combine with ketones and aldehydes to form interesting derivatives, which we will discuss in Chapter 18. The following reactions show the hydrolysis of two such derivatives. Propose mechanisms for these reactions.

(a)

(b)

Short Answer

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(a) The chemical reaction that takes place between an organic compound and water to give new compounds is called hydrolysis.There will be a cleavage of chemical bonds during the formation of new compounds.

Step by step solution

01

About hydrolysis

(a) The chemical reaction that takes place between an organic compound and water to give new compounds is called hydrolysis.There will be a cleavage of chemical bonds during the formation of new compounds.

02

About the given reaction

In this reaction, there is an opening of the ring where carbonyl and alcoholic groups get attached at the terminals. Another product will be methanol. The reaction takes place in the presence of an acid and water molecule.

03

About the mechanism

The mechanism of the reaction is given below.

04

About the given reactant

(b) The IUPAC name for the given reactant is 2,3,4,5,6,7-hexahydrobenzofuran. The word hydro stands for the presence of hydrogen. There is one double bond in the cyclic ring of six carbons.

05

About the chemical reaction

The given reactant opens its ring where it bears an oxygen atom. One terminal becomes a keto group, and the other becomes an alcoholic group.

06

About the mechanism

In this mechanism, the ring opening takes place by the treatment of an acid. Then, the intermediate obtained is treated with water to get the final product. The mechanism is shown below.

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Most popular questions from this chapter

Under normal circumstances, tertiary alcohols are not oxidized. However, when the tertiary alcohol is allylic, it can undergo a migration of the double bond (called an allylic shift) and subsequent oxidation of the alcohol. A particularly effective reagent for this reaction is Bobbitt’s reagent, similar to TEMPO used in many oxidations. (M. Shibuya et al., J. Org. Chem., 2008, 73, 4750.)

Show the expected product when each of these 3° allylic alcohols is oxidized by Bobbitt’s reagent.

(a)

(b)

(c)

(d)

Show how you would convert butan-1-ol to the following compounds using tosylate intermediates. You may use whatever additional reagents are needed.

(a)1-bromobutane (b)butan-1-amine, CH3CH2CH2CH2NH2

(c)butyl ethyl ether, CH3CH2CH2CH2OCH2CH3 (d)pentannitrile, CH3CH2CH2CH2CN

Use resonance forms of the conjugate bases to explain why methanesulfonic acid (CH3SO3H,pKa= -2.6) is a much stronger acid than acetic acid (CH3COOH,pKa =4.8)

The following pseudo-syntheses (guaranteed not to work) exemplify a common conceptual error.

(a)What is the conceptual error implicit in these syntheses?

(b)Propose syntheses that are more likely to succeed.

(a) The reaction of butan-2-ol with concentrated aqueous HBr goes with partial racemization, giving more inversion than retention of configuration. Propose a mechanism that accounts for racemization with excess inversion.

(b)Under the same conditions, an optically active sample of trans-2-bromocyclopentanol reacts with concentrated aqueous HBr to give an optically inactive product, (racemic) trans-1,2-dibromocyclopentane. Propose a mechanism to show how this reaction goes with apparently complete retention of configuration, yet with racemization. (Hint: Draw out the mechanism of the reaction of cyclopentene with in water to give the starting material, trans-2- bromocyclopentanol. Consider how parts of this mechanism might be involved in the reaction with HBr.)

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