A chronic alcoholic requires a much larger dose of ethanol as an antidote to methanol poisoning than does a nonalcoholic patient. Suggest a reason why a larger dose of the competitive inhibitor is required for an alcoholic.

Short Answer

Expert verified

A larger dose of the competitive inhibitor is needed for a chronic alcoholic patient as the individual comprises greater amounts of alcohol dehydrogenase in the body.

Step by step solution

01

Chronic alcoholic

Chronic alcoholism constitutes a chromic disease comprising genetic and environmental factors impacting its development. Some signs of chromic alcoholism include craving alcohol and physical dependence.

02

Competitive inhibitor

Competitive inhibition happens when a substrate(S)and inhibitor(I) link to the same site of a particular enzyme. It creates a barrier on the active site and prohibits the substrate binding.

03

Reason why a larger dose of the competitive inhibitor is required for an alcoholic

A chronic alcoholic possesses a high amount of alcohol dehydrogenase in the body. Hence, a large amount of ethanol is needed to balance the alcohol (alcohol dehydrogenase). When intravenous alcohol is provided to the methanol poisoning patients , ethanol inhibits the enzyme ADH.

The reabsorption of water from urine does not occur in the absence of ADH. Hence, the urine is dilute and the amount of water content is greater in it.

So, ethanol forces the excretory system to produce more urine. The individual excretes more water than the net water consumption. Hence, it excretes most of the methanol with water before it gets oxidized into formic acid.

Hence, a larger dose of the competitive inhibitor is needed for a chronic alcoholic patient as the individual comprises greater amounts of alcohol dehydrogenase in the body.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Classify each reaction as an oxidation, a reduction, or neither.

To practice working through the early parts of a multistep synthesis, devise syntheses of

(a) pentan-3-one from alcohols containing no more than three carbon atoms.

(b) 3-ethylpentan-2-one from compounds containing no more than three carbon atoms.

Compound A is an optically active alcohol. Treatment with chromic acid converts A into a ketone, B. In a separate reaction, A is treated with PBr3, converting A into compound C. Compound C is purified, and then it is allowed to react with magnesium in ether to give a Grignard reagent, D. Compound B is added to the resulting solution of the Grignard reagent. After hydrolysis of the initial product (E), this solution is found to contain 3,4 dimethylhexan-3-ol. Propose structures for compounds A, B, C, D, and E.

Suggest the most appropriate method for each of the following laboratory syntheses. In each case, suggest both a chromium reagent and a chromium-free reagent

(a) butan - 1 - ol → butanal, CH3CH2CH2CHO

(b) but - 2 - en - 1 - ol → but - 2 - enoic acid, CH3CH = CHCOOH

(c) butan - 2 - ol → butan - 2 - one, CH3COCH2CH3

(d) cyclopentanol → 1 - cyclopentylpropan - 1 - ol (twosteps)

(e) cyclopentyclohexanol → 2 - methylcyclohexanone (several steps)

(f) 1 - methylcyclohexanol → 2 - methylcyclohexanone (several steps)

Two products are observed in the following reaction.

(a) Suggest a mechanism to explain how these two products are formed.

(b) Your mechanism for part (a) should be different from the usual mechanism of the reaction of SOCl2 with alcohols. Explain why the reaction follows a different mechanism in

this case.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free