Propose a mechanism to show how 3,3-dimethylbut-1-ene reacts with dilute aqueous H2SO4to give 2,3-dimethylbutan-2-ol and a small amount of 2,3-dimethylbut-2-ene.

Short Answer

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3,3-dimethyl-but-1-ene in dilute aqueous acidic conditions undergo protonation on alkene carbon first which leads to the formation of a carbocation intermediate. In the next step, there occurs rearrangement that is, methyl shift, to form the more stable tertiary carbocation.

Formation of carbocation intermediate and methyl shift

Step by step solution

01

Step-1. Formation of carbocation intermediate and methyl shift

3,3-dimethyl-but-1-ene in dilute aqueous acidic conditions undergo protonation on alkene carbon first which leads to the formation of a carbocation intermediate. In the next step, there occurs rearrangement that is, methyl shift, to form the more stable tertiary carbocation.

Formation of carbocation intermediate and methyl shift

02

Step-2. Formation of products 2,3-dimethyl-butan-2-ol and 2,3-dimethyl-but-2-ene

Formation of major and minor products

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One of the principal components of lemongrass oil is limonene, C10H16. When limonene is treated with excess hydrogen and a platinum catalyst, the product is an alkane of formulaC10H20. What can you conclude about the structure of limonene?

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