Question: Draw a line-angle formula for each compound in Problem.

The line–angle formula is a shorthand formula for biological structures, often described as skeletal or stick figures.Line–angle formulas are frequently employed for cyclic compounds, although they are also utilized for non-cyclic compounds.

The given compound is CH₃COCH₂CHCHCOOH . The line-angle structure of the given compound is as follows:

Line-angle formula of CH₃COCH₂CHCHCOOH

The given compound has a six-carbon chain. In the given compound, the hydroxy group is attached to the first carbon of the chain. Oxygen is also attached to the first carbon with a double bond. There is a double bond between the chain's second and third carbon atoms. Another oxygen atom is attached to the fifth carbon with a double bond.

The given compound is NCCH₂COCH₂CHO . The line-angle structure of the given compound is as follows:

Line-angle formula of NCCH₂COCH₂CHO

The given compound has a five-carbon chain. In the given compound, nitrogen is attached to the first carbon of the chain. Oxygen atoms are attached to the third and fifth carbon of the chain with a double bond.

The given compound is CH₂CHCH(OH)CH₂CO₂H . The line-angle structure of the given compound is as follows:

Line-angle formula of CH₂CHCH(OH)CH₂CO₂H

The given compound has a five-carbon chain. In the given compound, the hydroxy group is attached to the third carbon of the chain. Oxygen atoms are attached to the first carbon of the chain with a double bond. There is a double bond between the fourth and fifth carbon.

The given compound is CH₂CHC(CH)CHCOOCH₃ . The line-angle structure of the given compound is as follows:

Line-angle formula of CH₂CHC(CH)CHCOOCH₃

The given compound has seven carbon atoms. There is a double bond at the second and fourth carbon and one methyl substitution on the third carbon. The oxygen atom is attached to the first carbon with a double bond. Another oxygen is attached with a single bond to the first carbon and methyl group.