Show how you would synthesize the following alcohols by reducing appropriate carbonyl compounds.

a. Heptan-1-ol (b) Heptan-2-ol (c) 2-methylhexan-2-ol

b.


Short Answer

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Answer

(a)

(b)

2-heptanone heptan-2-ol

(c)

2-methyl-3-hexanone 2-methyl hexan-3-ol

(d)

Step by step solution

01

Reduction with reducing agent 

The synthesis of the compound upon reduction with reducing agentsNaBH4is LiAIH4thatdoes not reduce the ester and acid group whereas the ester group is reduced byLiAIH4.

02

Formation of the desired product with reducing agent

(a)The heptan-1-ol is formed by the reaction of heptanal either NaBH4 in the presence of CH3OH or by the reaction LiAI4 with H3O+

Heptan-1-al heptan-1-ol

b. The heptan-2-ol is formed by the reaction of 2 heptanone either NaBH4 in the presence of CH3OH or by the reaction LiAI4 with H3O+

2-heptanone heptan-2-ol

c.The 2-methyl hexan-3 ol is formed by the reaction of 2-methyl-3-hexanone either NaBH4 in the presence of CH3OH or by the reaction LiAIH4 with H3O+

2-methyl-3-hexanone 2-methyl hexan-3-ol

d. In this reaction, the desired product will not be formed by the reaction of the reactant LiAIH4 as it also reduces the ester group in addition to the ketone group whereas the NaBH4 will reduce only the ketone group. So, this reaction is possible only with NaBH4


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