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Chapter 4: Q27P (page 223)

Write an equation for the reaction of vitamin E with an oxidizing radical (RO·) to give ROH and a less reactive free radical.

Short Answer

Expert verified

Radical inhibitors help to protect the cells of living systems. Vitamin E is a phenol (an aromatic ring with an -OH group), and it is thought to react with radicals by losing the OH hydrogen atom.

Step by step solution

01

Role of radical inhibitor

Radical inhibitors help to protect the cells of living systems. Vitamin E is a phenol (an aromatic ring with an -OH group), and it is thought to react with radicals by losing the OH hydrogen atom.

02

Step 2:

Abstracting of a proton from Vitamin E by oxidizing radical (RO·) results in free radical. This free radical is stabilized by resonance as shown in above diagram.

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Most popular questions from this chapter

When exactly 1 mole of methane is mixed with exactly 1 mole of chlorine and light is shone on the mixture, a chlorination reaction occurs. The products are found to contain substantial amounts of di-, tri-, and tetrachloromethane, as well as unreacted methane.

(a) Explain how a mixture is formed from this stoichiometric mixture of reactants, and propose mechanisms for the formation of these compounds from chloromethane.

(b) How would you run this reaction to get a good conversion of methane toCH3Cl? Of methane to CCl4?

Predict the ratios of products that result from chlorination of isopentane.(2-methylbutane)

Question: Under base-catalyzed conditions, two molecules of acetone can condense to form diacetone alcohol. At room temperature250c, aboutof 5%the acetone is converted to diacetone alcohol. Determine the value of∆G0for this reaction.

When a small amount of iodine is added to a mixture of chlorine and methane, it prevents chlorination from occurring. Therefore, iodine is a free-radical inhibitor for this reaction. CalculateΔH0values for the possible reactions of iodine with species present in the chlorination of methane and use these values to explain why iodine inhibits the reaction. (The I-Clbond-dissociation enthalpy is 211 kJ/molor 50 kcal/mol).

Question: Draw Lewis structures for the following free radicals.

(a)The ethyl radical, CH3-CH2

(b)The tert butyl radical, (CH3 )3C

(c)The isopropyl radical,(2-propyl radical)

(d)The iodine atom
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