Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 4: Q33P (page 233)

When it is strongly heated, methyl diazoacetate decomposes to give a nitrogen gas and a carbene. Draw a Lewis structure of the carbene.

Short Answer

Expert verified

Carbenes may be defined as a neutral divalent chemical species containing a carbon atom consisting six electrons in their valence shell. Out of six electrons, two electrons are unshared. The simplest carbene is methylene .

Step by step solution

01

Carbenes

Carbenes may be defined as a neutral divalent chemical species containing a carbon atom consisting six electrons in their valence shell. Out of six electrons, two electrons are unshared. The simplest carbene is methylene .

02

Lewis structures

The formation of covalent bond in molecules is shown in an easier way by Lewis structures. The valence electrons are represented by dots in the Lewis structure and one bond is represented as two electrons. In drawing Lewis structures, the atoms are arranged in such a way that all of them have eight valence electrons. The exception is with hydrogen, which can have a maximum of two valence electrons.

03

Decomposition of methyl diazoacetate to nitrogen and carbene

04

Lewis structure of carbene

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Question: When ethene is mixed with hydrogen in the presence of a platinum catalyst, hydrogen adds across the double bond to form ethane. At room temperature, the reaction goes to completion. Predict the signs ∆H0and∆S0for this reaction. Explain these signs in terms of bonding and freedom of motion.

Iodination of alkanes using iodine (I2)is usually an unfavorable reaction. (See problem 4-17, for example). Tetraiodomethane (Cl4) can be used as the iodine source for iodination in the presence of a free-radical initiator such as hydrogen peroxide. Propose a mechanism (involving mildly exothermic propagation steps) for the following proposed reaction. Calculate the value of ΔHfor each of the steps in your proposed mechanism.

The following bond-dissociation energies may be helpful:

(a) Draw the structure of the transition state for the second propagation step in the chlorination of methane.

Show whether the transition state is product-like or reactant-like and which of the two partial bonds is stronger.

(b) Repeat for the second propagation step in the bromination of methane.

Question: (a) Use bond-dissociation enthalpies from Table 4-2 (page 203), calculate the heat of reaction for each step in the free-radical bromination of methane.

(b) Calculate the overall heat of reaction.

Question: Each of the following proposed mechanisms for the free-radical chlorination of methane is wrong. Explain how the experimental evidence disproves each mechanism.

(a)

CI2+hv→CI2(anactivatedformofCI2)CI2+CH4→HCl+CH3Cl(b)CH4+hv→CH3+HCH3+Cl2→CH3Cl+ClCl+H→HCl
See all solutions

Recommended explanations on Chemistry Textbooks

Inorganic Chemistry

Read Explanation

The Earths Atmosphere

Read Explanation

Making Measurements

Read Explanation

Chemical Analysis

Read Explanation

Physical Chemistry

Read Explanation

Kinetics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free