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Chapter 5: Q1TP (page 225)

Draw curved arrows to show the movement of the electrons in the following reaction steps.

Short Answer

Expert verified

• As new covalent bonds are formed, and existing covalent bonds are destroyed, electrons move in curved arrows.

• Each arrow represents the movement of two electrons (an electron pair) from a single atom to an electrophile (nucleophile) at the end of the arrow (at the point of the arrow).

• The arrow's tail denotes the location of the reactant's electrons; the tail always starts at a lone pair or a bond.

• The arrow's head always points to an atom or a bond, indicating where these same electrons end up in the result.

Step by step solution

01

The first step is to use a curved arrow

• As new covalent bonds are formed, and existing covalent bonds are destroyed, electrons move in curved arrows.

• Each arrow represents the movement of two electrons (an electron pair) from a single atom to an electrophile (nucleophile) at the end of the arrow (at the point of the arrow).

• The arrow's tail denotes the location of the reactant's electrons; the tail always starts at a lone pair or a bond.

• The arrow's head always points to an atom or a bond, indicating where these same electrons end up in the result.

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Most popular questions from this chapter

Draw curved arrows to show the movement of the electrons that result in formation of the given product(s).

Use what the curved arrows tell you about electron movement to determine the product(s) of each reaction step.

Question: Draw the structure for each of the following:

a. 3,3-dimethylcyclopentene

b. 6-bromo-2,3-dimethyl-2-hexene

c. ethyl vinyl ether

d. allyl alcohol

Question: Which of the following are electrophiles, and which are nucleophiles?

a. For a reaction with ∆H° = -12 kcal/mol and ∆S° = 0.01kcal mol-1 K-1, calculate the ∆G° and the equilibrium constant at: 1. 30 °C and 2. 150 °C.

b. How does ∆G° change as T increases?

c. How does Keq change as T increases?
See all solutions

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