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Chapter 5: Q1TP (page 225)

Draw curved arrows to show the movement of the electrons in the following reaction steps.

Short Answer

Expert verified

• As new covalent bonds are formed, and existing covalent bonds are destroyed, electrons move in curved arrows.

• Each arrow represents the movement of two electrons (an electron pair) from a single atom to an electrophile (nucleophile) at the end of the arrow (at the point of the arrow).

• The arrow's tail denotes the location of the reactant's electrons; the tail always starts at a lone pair or a bond.

• The arrow's head always points to an atom or a bond, indicating where these same electrons end up in the result.

Step by step solution

01

The first step is to use a curved arrow

• As new covalent bonds are formed, and existing covalent bonds are destroyed, electrons move in curved arrows.

• Each arrow represents the movement of two electrons (an electron pair) from a single atom to an electrophile (nucleophile) at the end of the arrow (at the point of the arrow).

• The arrow's tail denotes the location of the reactant's electrons; the tail always starts at a lone pair or a bond.

• The arrow's head always points to an atom or a bond, indicating where these same electrons end up in the result.

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Most popular questions from this chapter

a. For a reaction with ∆H° = -12 kcal/mol and ∆S° = 0.01kcal mol-1 K-1, calculate the ∆G° and the equilibrium constant at: 1. 30 °C and 2. 150 °C.

b. How does ∆G° change as T increases?

c. How does Keq change as T increases?

Question: Determine the degree of unsaturation and then draw possible structures for noncyclic compounds with the following molecular formulas:

a. C3H6

b. C3H4

c. C4H6

Draw curved arrows to show the movement of the electrons that result in the formation of the given product(s). (Hint: Look at the structure of the product to see what bonds need to be formed and broken in order to arrive at the structure of the desired product.)

What is the molecular formula for each of the following?

  1. a 4-carbon hydrocarbon with two p bonds and no rings
  2. a 10-carbon hydrocarbon with one p bond and 2 rings

Use what the curved arrows tell you about electron movement to determine the product(s) of each reaction step.
See all solutions

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