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Chapter 5: Q21 P (page 205)

a. For which reaction in each set will ∆S° be more significant?

b. For which reaction will ∆S° be positive?

Short Answer

Expert verified
  2. Noun

Step by step solution

01

 Definition of ∆S°-

Entropy is a measure of a system's freedom of motion.

∆S° = products' freedom of motion minus reactants' freedom of motion

02

 ∆S° value will be more significant if the number of molecules of reactant differs from the number of molecules in the product.

Also, we will see at which reaction ∆S° is positive.

Therefore, ∆S° will be more significant for the above reactions.

03

None of the four reactions have a ∆S°.

The product must have more freedom of motion than the reactant in order to have a positive S°. In other words, there should be more product molecules than reactant molecules.

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Most popular questions from this chapter

Draw structures for the following:

a. (2E,4E)-1-chloro-3-methyl-2,4-hexadiene

b. (3Z,5E)-4-methyl-3,5-nonadiene

c. (3Z,5Z)-4,5-dimethyl-3,5-nonadiene

d. (3E,5E)-2,5-dibromo-3,5-octadiene

a. Which is the most stable: 3,4-dimethyl-2-hexene, 2,3-dimethyl-2-hexene, or 4,5-dimethyl-2-hexene?

b. Which compound has the largest heat of hydrogenation?

c. Which compound has the smallest heat of hydrogenation?

Draw curved arrows to show the flow of electrons responsible for the conversion of the reactants to products

In a reaction in which reactant A is in equilibrium with product B at

25 °C, what relative amounts of A and B are present at equilibrium if ΔG° at 25 °C is

a. 2.72 kcal/mol?

b. 0.65 kcal/mol?

c. -2.72 kcal/mol?

d. -0.65 kcal/mol?

How many of the following names are correct? Correct the incorrect names.

a. 3-pentene

b. 2-octene

c. 2-vinylpentane

d. 1-ethyl-1-pentene

e. 5-ethylcyclohexene

f. 5-chloro-3-hexene

g. 2-ethyl-2-butene

h. (E)-2-methyl-1-hexene

i. 2-methylcyclopentene
See all solutions

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