In a reaction in which reactant A is in equilibrium with product B at

25 °C, what relative amounts of A and B are present at equilibrium if ΔG° at 25 °C is

a. 2.72 kcal/mol?

b. 0.65 kcal/mol?

c. -2.72 kcal/mol?

d. -0.65 kcal/mol?

Short Answer

Expert verified

a. The relative amount of A and B are 1 and 0.01 respectively.

b. The relative amount of A and B are 1 and 0.33 respectively.

c. The relative amount of A and B are 1 and 90 respectively.

d. The relative amount of A and B are 1 and 2.97 respectively.

Step by step solution

01

Explanation of formula

In an equilibrium reaction,

k1

A ⇌ B

k-1

From this, we can say, and the relation between kequi and ΔG° is equal to

ΔG° = -RTln(kequi)

02

calculation

  1. whenΔG° = 2.72 kcal/mol,

2.72 kcal/mol = -1.987 x 298 x In ( kequi )

In kequi =

The relative amount of A and B are 1 and 0.01 respectively.

b. when ΔG° = 0.65 kcal/mol,

0.65 kcal/mol = -1.987 x 298 x In(kequi )


The relative amount of A and B are 1 and 0.33 respectively.

  1. whenΔG° = -2.72 kcal/mol,

The relative amount of A and B are 1 and 90 respectively.

  1. whenΔG° = -0.65 kcal/mol,

The relative amount of A and B are 1 and 2.97 respectively.

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