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Chapter 5: Q6TP (page 229)

Draw curved arrows to show the movement of the electrons that result in formation of the given product(s).

Short Answer

Expert verified

• As new covalent bonds are formed and existing covalent bonds are destroyed, electrons move in curved arrows.

• Each arrow represents the movement of two electrons (an electron pair) from a single atom to an electrophile (nucleophile) at the end of the arrow (at the point of the arrow).

• The arrow's tail denotes the location of the reactant's electrons; the tail always starts at a lone pair or a bond.

• The arrow's head always points to an atom or a bond, indicating where these same electrons end up in the result.

Step by step solution

01

The first step is to use a curved arrow.

• As new covalent bonds are formed and existing covalent bonds are destroyed, electrons move in curved arrows.

• Each arrow represents the movement of two electrons (an electron pair) from a single atom to an electrophile (nucleophile) at the end of the arrow (at the point of the arrow).

• The arrow's tail denotes the location of the reactant's electrons; the tail always starts at a lone pair or a bond.

• The arrow's head always points to an atom or a bond, indicating where these same electrons end up in the result.

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Most popular questions from this chapter

Which is more stable?

Question: Determine the degree of unsaturation for hydrocarbons with the following molecular formulas:

a. C20H34 b. C8H16 c. C12H20 d. C40H56

Question: a. How many vinylic hydrogens does cyclopentene have?

b. How many allylic hydrogens does it have?

Question: Draw the structure for each of the following:

a. 3,3-dimethylcyclopentene

b. 6-bromo-2,3-dimethyl-2-hexene

c. ethyl vinyl ether

d. allyl alcohol

What is the molecular formula for each of the following?

  1. a 4-carbon hydrocarbon with two p bonds and no rings
  2. a 10-carbon hydrocarbon with one p bond and 2 rings
See all solutions

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