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Chapter 5: Q9P (page 190)

Question: Draw the structure for each of the following:

a. 3,3-dimethylcyclopentene

b. 6-bromo-2,3-dimethyl-2-hexene

c. ethyl vinyl ether

d. allyl alcohol

Short Answer

Expert verified

Vinylic carbons are the sp2carbons in an alkene and a vinylic hydrogen is a hydrogen bound to a vinylic carbon.

Step by step solution

01

Definition of vinylic hydrogens- 

Vinylic carbons are the sp2carbons in an alkene and a vinylic hydrogen is a hydrogen bound to a vinylic carbon.

02

Definition of allylic hydrogens-

An allylic carbon is a sp3carbon that is next to a vinylic carbon., whereas an allylic hydrogen is a hydrogen attached to an allylic carbon.

In common names, two groups with a carbon–carbon double bond are used: the vinyl group as well as the allyl group.

The vinyl group is the lowest possible group that contains a vinylic carbon, and it is made up of two atoms.

The allyl group is the smallest conceivable allylic carbon-containing group.

When a substituent is used in a name, it must be connected to the vinylic or allylic carbon, accordingly.

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Most popular questions from this chapter

From the following rate constants, determined at five temperatures, calculate the experimental energy of activation and ΔG±,ΔH±,andΔS±for the reaction at 30°C:

a. Which of the following reactions will have the larger ΔS° value?

b. Will the ΔS° value be positive or negative?\

Question: Identify the nucleophile and the electrophile in the following acid–base reactions:

Question: a. Which of the monosubstituted cyclohexanes in Table 3.9 on p. 128 has a negative ∆G° for the conversion of an axial-substituted chair conformer to an equatorial-substituted chair conformer?

b.Which monosubstituted cyclohexane has the most negative ∆G° for this conversion?

c. Which monosubstituted cyclohexane has the greatest preference for an equatorial position?

d. Calculate ∆G° for the conversion of “axial” methylcyclohexane to “equatorial” methylcyclohexane at 25 °C.

Draw curved arrows to show the movement of the electrons that result in formation of the given product(s).
See all solutions

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