Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 5: Q9TP (page 230)

Draw curved arrows to show the movement of the electrons in each step of the following reaction sequences.

Short Answer

Expert verified

The first step is to use a curved arrow.

• As new covalent bonds are formed and existing covalent bonds are destroyed, electrons move in curved arrows.

• Each arrow represents the movement of two electrons (an electron pair) from a single atom to an electrophile (nucleophile) at the end of the arrow (at the point of the arrow).

• The arrow's tail denotes the location of the reactant's electrons; the tail always starts at a lone pair or a bond.

• The arrow's head always points to an atom or a bond, indicating where these same electrons end up in the result.

Step by step solution

01

Step-by-Step Solution

The first step is to use a curved arrow.

• As new covalent bonds are formed and existing covalent bonds are destroyed, electrons move in curved arrows.

• Each arrow represents the movement of two electrons (an electron pair) from a single atom to an electrophile (nucleophile) at the end of the arrow (at the point of the arrow).

• The arrow's tail denotes the location of the reactant's electrons; the tail always starts at a lone pair or a bond.

• The arrow's head always points to an atom or a bond, indicating where these same electrons end up in the result.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

From the following rate constants, determined at five temperatures, calculate the experimental energy of activation and ΔG±,ΔH±,andΔS±for the reaction at 30°C:

Draw structures for the following:

a. (2E,4E)-1-chloro-3-methyl-2,4-hexadiene

b. (3Z,5E)-4-methyl-3,5-nonadiene

c. (3Z,5Z)-4,5-dimethyl-3,5-nonadiene

d. (3E,5E)-2,5-dibromo-3,5-octadiene

What is the molecular formula for each of the following?

  1. a 4-carbon hydrocarbon with two p bonds and no rings
  2. a 10-carbon hydrocarbon with one p bond and 2 rings

Question: a. How many vinylic hydrogens does cyclopentene have?

b. How many allylic hydrogens does it have?

Squalene, a hydrocarbon with the molecular formula C30H50, is obtained from shark liver. (Squalus is Latin for “shark.”) If squalene is an acyclic compound, how many π bonds does it have?
See all solutions

Recommended explanations on Chemistry Textbooks

Chemical Reactions

Read Explanation

Kinetics

Read Explanation

Ionic and Molecular Compounds

Read Explanation

Making Measurements

Read Explanation

Physical Chemistry

Read Explanation

Chemical Analysis

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free