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Chapter 4: Q2P (page 145)

Draw the cis and trans isomers for the following:

a. 1-bromo-4-chlorocyclohexane

b. 1-ethyl-3-methylcyclobutane

Short Answer

Expert verified

The cis and trans isomers are given below, they acquire these structures due to the stability and avoiding steric hindrance.

Step by step solution

01

 Step 1: Definition of isomer

Isomers are those which have the same atoms in space but the linkage and their spatial orientations are different.

02

The probable cis-trans isomers of 1-bromo-4-chlorocyclohexane.

The conformer with the bulkier group at the equatorial position is always more stable as it avoids the 1,3-diaxial interaction and therefore the strain in the ring.

03

The probable cis-trans isomers of 1-ethyl-3-methylcyclobutane.

Here, the cis form is more stable because of the absence of 1,3-diaxial interaction.

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Most popular questions from this chapter

Using skeletal structures, draw the stereoisomers of

a. 2,4-dichloroheptane. b. 2,4-dichloropentane.

Draw all possible stereoisomers for each of the following. Indicate those compounds for which no stereoisomers are possible.

a. 1-bromo-2-chlorocyclohexane

b. 2-bromo-4-methylpentane

c. 1,2-dichlorocyclohexane

d. 2-bromo-4-chloropentane

e. 1-bromo-4-chlorocyclohexane

f. 1,2-dimethylcyclopropane

g. 4-bromo-2-pentene

h. 3,3-dimethylpentane

i. 1-bromo-2-chlorocyclobutane

j. 1-bromo-3-chlorocyclobutane

a. How many asymmetric centers does the following compound have?

b. How many stereocenters does it have?

Do the following compounds have the E or the Z configuration?

Draw the sterioisomers of 2-methylcyclohexanol.
See all solutions

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